ASAP Please!

The base protonation constant Kb of allantoin (C4H4N3O3NH2) is ×9.1210−6. Calculate the pH of a 1.1M solution of allantoin at 25

larisa [96]

Answer:

pH= 11.5

Explanation:

To the calculation of the pH value, we need to write the ionization equation first. Then using the ICE table and the information given by the problem we can set up the problem:

$C_4H_4N_3O_3NH_2~+~H_2O->C_4H_4N_3O_3NH_3^+~+~OH^-$

I 1.1 M Zero Zero

C -X +X +X

E 1.1-X X X

As next step, using the equilibrium expression for Kb we can replace the terms find in the ICE table and then solve for X, so:

$Kb=\frac{[C_4H_4N_2O_3NH_3^+][OH^-]}{[C_4H_4N_3O_3NH_2]}$

$9.2x10^-^6=\frac{[X][X]}{[1.1-X]}$

$9.2x10^-^6=\frac{X^2}{1.1-X}$

$(9.2x10^-^6)*[1.1-X]=X^2$

$1.01x10^-^5~-9.2x10^-^6X-X^2=0$

$X=0.003173$

With the value of X we can find the pOH (lets remember that X is the concentration of OH-), so:

$pOH=-Log(0.003173)$

$pOH=2.50$

Finally, we can find the pH value with the equation:

$14~=~pH~+~pOH$

$14~=~2.5~+~pOH$

$pH=14-2.5$

$pH=11.5$

The 1.1 M allantoin solution have a pH value of 11.5

4 0

3 years ago

I need help on #2 a and b. please explain steps and answer

shtirl [24]

Hope this helps you.

8 0

3 years ago

To what volume (in milliliters) should you dilute 100.0 mL of a 5.50 M solution of CaCl2 solution to obtain a 0.950 M solution o

Alexxx [7]

Dilution law is given as:

$M_{1}V_{1}=M_{2}V_{2}$ (1)

where, $M_{1}$ = molarity of initial concentrated solution.

$V_{1}$ = volume of initial concentrated solution.

$M_{2}$ = molarity of final diluted solution.

tex]V_{2}[/tex] = volume of final diluted solution.

Volume of initial concentrated solution of $CaCl_{2}$ = 100.0 mL

Molarity of initial concentrated solution of $CaCl_{2}$ = 5.50 M

Volume of final diluted solution of $CaCl_{2}$ = 0.950 M

Put the values in formula (1),

$5.50 M\times 100.0 mL=0.950 M\times V_{2}$

$V_{2} =\frac{5.50 M\times 100.0 mL}{0.950 M}$

$V_{2} =578.9 mL$

Hence, final diluted volume of the solution is $578.9 mL$ .

3 0

4 years ago

Differentiate between ideal and non - ideal solutions. <img src="https://tex.z-dn.net/?f=%20%5C%5C%20" id="TexFormula1" title

nordsb [41]

Answer:

Ideal Solution: An ideal solution is a solution where interactions between molecules are identical between all the molecules in the solution. Non ideal Solution: A non ideal solution is a solution that has differences in the interactions between molecules of different components in the solution.

Explanation:

3 0

2 years ago

Read 2 more answers

Balancing equations

Bad White [126]

Make sure you numbers with variable are on one side and the numbers

7 0

4 years ago