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dimulka [17.4K]
3 years ago
5

The reactants in a chemical equation have 3 carbon atoms, 6 oxygen atoms, and 4 hydrogen atoms. In order to follow the conservat

ion of matter, the products of the chemical equation will have
Chemistry
1 answer:
Anon25 [30]3 years ago
8 0

Answer:

The same amount of atoms (3 carbon atoms, 6 oxygen atoms, and 4 hydrogen atoms).

Explanation:

According to the law of conservation of mass, when a chemical reaction takes place there is no synthesis or degradation of matter, that is, <em>matter can be neither created nor destroyed</em>. It can only be transformed.

Therefore, in a <u>chemical reaction the atoms are conserved</u>. That means that the elements that in definite proportions are forming a compound, will reorganize to form new compounds, and <u>the amount and type of atoms of the products will be the same as the reactants</u>.

In summary, if the reactants in a chemical equation have 3 carbon atoms, 6 oxygen atoms, and 4 hydrogen atoms, the products of the chemical equation will have 3 carbon atoms, 6 oxygen atoms, and 4 hydrogen atoms as well.

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How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o
Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

Density (\rho)=\frac{Mass(m)}{Volume(V)}

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,  

334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)

334x+x\times 11.976=29553.16

345.976x = 29553.16

x = 85.4197 kg

Thus,  

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0
4 years ago
Given 6.0 mol of N2 are mixed with 12.0 mol of H2. Equation: N2 + 3H2--&gt; 2NH3
andrey2020 [161]
1) Excess reagent

1 mol N2 / 3 mol H2

6.0 mol N2 *3 mol H2 / 1 mol N2 = 18 mol H2

18mol H2 > 12 mol H2 =>  H2 is limiting (you  need 18 mol H2 to use all the 6 mol N2), then N2 is in excees.

12.0 mol H2 * 1mol N2/ 3 mol H2  = 4 mol N2 is the quantity that will react, then the excess is 6 mol N2 - 4 mol N2 = 2 mol N2

2) NH3 produced

12 mol H2 * [2 mol NH3 / 3 mol H2] = 8 mol NH3

Aslso, 4 mol N2 *[2molNH3 / 1 molN2] = 8 mol NH3, the same result.

3) Yield

80% * 8 mol NH3 = 6.4 mol NH3
5 0
3 years ago
How many hydrogen ions (H+) are in a mole?
ratelena [41]
6.02 × 10^23 hydrogen ions per mol
3 0
3 years ago
Surface ocean currents curve to the right in the northern hemisphere because
kobusy [5.1K]

Answer:

Esto se debe a la rotación de la tierra

Explanation:

3 0
3 years ago
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What did the photoelectric experiment demonstrate?
exis [7]

Answer: C. Light can cause electrons to be released from the surface of a metal

Explanation:

4 0
3 years ago
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