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Reika [66]
3 years ago
14

What is coloumbs law

Physics
2 answers:
kolbaska11 [484]3 years ago
7 0

Coulomb's law, or Coulomb's opposite square law, is a trial law of material science that measures the measure of power between two stationary, electrically charged particles. The electric power between charged bodies very still is customarily called electrostatic power or Coulomb power.

Andrej [43]3 years ago
6 0

Answer:

Explanation:

Coulumbs law states that the force of attraction or repulsion between two charges,Q and q is directly proportional to the charges and inversely proportional to the distance apart.

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The rate of motion of a lithospheric plate with respect to a stationary location inside Earth is termed __________ plate velocit
AlekseyPX

Answer:

1. Absolute plate velocity.

2. Relative plate velocity.

Explanation:

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If an object is in equilibrium, which of the following statements is NOT true?
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4 years ago
The critical angle for a substance is measured at 53.7 degrees. light enters from air at 45.0 degrees. at what angle it will con
faust18 [17]
When light travels from a medium with greater refractive index n_1 to a medium with smaller refractive index n_2, there exists an angle (called critical angle) above which the light is totally reflected, and the value of this angle is given by
\theta_c = \arcsin ( \frac{n_2}{n_1} )
In this problem, we know that the critical angle is\theta_c = 53.7^{\circ}, so we can find the ratio between the refractive indices of the two mediums:
\frac{n_2}{n_1} = \sin \theta_c = \sin 53.7^{\circ} =0.81
and since the second medium is air (n=1.00), the refractive index of the first medium is
n_1=  \frac{n_2}{0.81}= \frac{1.00}{0.81}=1.23

In the second part of the problem, we have light entering from air (n_i = 1.00) at angle of incidence of \theta_i = 45.0 ^{\circ}, into the second medium with n_r = 1.23. By using Snell's law, we can find the angle of refraction of the light inside the medium:
n_i \sin \theta_i = n_r \sin \theta_r
\sin \theta_r =  \frac{n_i}{n_r}  \sin \theta_i = \frac{1.00}{1.23} \sin 45^{\circ}=0.574
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3 0
3 years ago
A Porsche 944 Turbo has a rated engine power of 217 hp. 30% of the power is lost in the drive train, and 70% reaches the wheels.
shutvik [7]

Answer:

a = 6.53 m/s^2

v = 11.5689 m/s

Explanation:

Given data:

engine power is 217 hp

70 % power reached to wheel

total mass ( car + driver) is 1530 kg

from the data given

2/3 rd of weight is over the wheel

w = 2/3rd mg

maximum force

F = \mu W

we know that F = ma

ma =  \mu (2/3 mg)

a_{max} = 2/3(1.00) (9.8) = 6.53 m/s^2

the new power is p  = 70\% P_[max} = 0.7 P_{max}

P =f_{max} v

0.7P_{max} = ma_{max} v

solving for speed v

v =0.7 \times \frac{P_{max}}{ma_{max}}

v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}

v = 11.5689 m/s

7 0
3 years ago
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