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____ [38]
4 years ago
5

How does tightening a string on a guitar affect its natural frequency?

Physics
2 answers:
Flauer [41]4 years ago
6 0

Well, this is the answer in which, will be selected as a correct answer, on a answer choice selection: the natural frequency increases


iragen [17]4 years ago
3 0
By tightening a string you are actually putting more stress on the string you are giving it a new frequency that isn't natural.

Hope this helps
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A car left point a at 7:30 am and arrived at point b, 162 miles away at 10:30 am. what was its average speed in miles per hour?5
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3 0
3 years ago
What is the correct definition of refraction?
scoray [572]

i believe it's C but i'm not completely sure

5 0
3 years ago
An assumption central to all scientific inquiry is causality, which means that
zavuch27 [327]
<h2>Answer</h2>

Causality means reason behind the process

<h2>Explanation</h2>

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7 0
3 years ago
A truck is hauling a 300-kg log out of a ditch using a winch attached to the back of the truck. Knowing the winch applies a cons
torisob [31]

Answer:

0.1 s

Explanation:

The net force on the log is F - f = ma where F = force due to winch = 2850 N, f = kinetic frictional force = μmg where μ = coefficient of kinetic friction between log and ground = 0.45, m = mass of log = 300 kg and g = acceleration due to gravity = 9.8 m/s² and a = acceleration of log

So F - f = ma

F - μmg = ma

F/m - μg = a

So, substituting the values of the variables into the equation, we have

a = F/m - μg

a = 2850 N/300 kg - 0.45 × 9.8 m/s²

a = 9.5 m/s² - 4.41 m/s²

a = 5.09 m/s²

Since acceleration, a = (v - u)/t where u = initial velocity of log = 0 m/s (since it was a rest before being pulled out of the ditch), v = final velocity of log = 0.5 m/s and t = time taken for the log to reach a speed of 0.5 m/s.

So, making t subject of the formula, we have

t = (v - u)/a

substituting the values of the variables into the equation, we have

t = (v - u)/a

t = (0.5 m/s - 0 m/s)/5.09 m/s²

t = 0.5 m/s ÷ 5.09 m/s²

t = 0.098 s

t ≅ 0.1 s

6 0
3 years ago
To the nearest tenth, what is the area of the shaded segment when JA=8ft ??
Murrr4er [49]
A=\dfrac{1}{6}\pi 8^2-\dfrac{8^2\sqrt{3}}{4}\approx 5.8\;[ft^2]
Answer: <span>C. 5.8 ft squared</span>
7 0
3 years ago
Read 2 more answers
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