Question

The critical angle for total internal reflection for cubic zirconia surrounded by air is 27.0°. Calculate the polarizing angle for cubic zirconia.

Answer 1

Answer:

Polarizing angle, $\theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}$

Given:

Critical angle, $\theta_{cr} = 27^{\circ}$

Solution:

Now, in Total Internal Reflection (TIR), the critical angle for cubic zirconia is given by:

$sin\theta_{cr} = \frac{1}{\mu_{Z}}$                      (1)

where

${\mu_{Z}$ = refractive index of zirconia

From eqn (1):

$\mu_{Z} = \frac{1}{sin\theta_{cr}}$

$\mu_{Z} = \frac{1}{sin(27^{\circ})} = 2.2$

Now, the angle of polarization is given by:

tan$\theta_{P} = \mu_{Z}$

Therefore,

$\theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}$