Is this a scientific model? Use complete sentences to explain why or why not.
1 answer:
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Answer:
θ = tan⁻¹ ()
Explanation:
This problem must be solved using projectile launch ratios. Let's analyze the situation, the projectile explodes at the highest point, therefore we fear the height (i = h), the speed at this point is the same, but the direction changes, we are asked to find the smallest angle of the speed in the point of arrival with respect to the x-axis.
The speed at the arrival point (y = 0)
v² = vₓ² + v_y²
Let's see how this angle changes, for two extreme values:
* The particle that falls from the point of explosion, in this case the speed is vertical
v = v_y
the angle with the horizontal is 90º
* The particle leaves horizontally from the point of the explosion, the initial velocity is horizontal
vₓ = v
the final velocity for y = 0
v_f = vₓ² + v_y²
therefore the angle has a value greater than zero and less than 90º
As they ask for the smallest angle, we can see that we must solve the last case
the output velocity is horizontal vₓ = v
Let's find the velocity when it hits the ground y = 0, with y₀ = h
=
- 2 g (y-y₀)
v_{y}^2 = - 2g (0- y₀)
let's calculate
v_{y}^2 = 2 9.8 h
we use trigonometry to find the angle
tan θ =
θ = tan⁻¹ ()
let's calculate
θ = tan⁻¹ ()
Answer:
Explanation:
The buoyant force F is equal to the weight of the displaced fluid. The weight of the displaced fluid is , where
is the mass of the displaced fluid. The mass of the displaced fluid is
, where
is the density of the fluid and
is the displaced volume, which is equal to the submerged volume of the cilinder
.
Putting all together we have:
Answer:
The magnitude of the net electric field is:
Explanation:
The electric field due to q1 is a vertical positive vector toward q1 (we will call it E1).
On the other hand, the electric field due to q2 is a horizontal positive vector toward q2(We will call it E2).
Knowing this, the <u>magnitude of the net electric</u> field will be the<u> E1 + E2. </u>
Let's find first E1 and E2.
The electric field equation is given by:
Where:
- k is the Coulomb constant (k = 9*10^{9} Nm²/C²)
- q1 is the first charge
- d1 is the distance from q1 to P
And E2 will be:
Finally, we need to use the Pythagoras theorem to find the magnitude of the net electric field.
I hope it helps you!