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Brums [2.3K]
3 years ago
12

How many solutions are there to the questiom below 6x+35+9x=15(x+4)-25

Mathematics
1 answer:
quester [9]3 years ago
6 0
6x+35+9x=15(x+4)-25\\\\15x+35=15x+60-25\\\\15x+35=15x+35

Answer: <span>infinitely many solutions</span>
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Use the standard algorithm to find the product of 853 and 59. Record the product of multiplying by the ones digit, the product o
bearhunter [10]

The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327

<h3>How to determine the product of the numbers?</h3>

The numbers are given as

853 and 59

By using the standard algorithm i.e. the partial product method, we have the following equation

853 * 59 = 853 * (50 + 9)

Open the bracket

So, we have

853 * 59 = 853 * 50 + 853 * 9

Evaluate the products

So, we have

853 * 59 = 42650 + 7677

The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650

Next, we evaluate the sum

853 * 59 = 50327

This means that the final product is 50327

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Step-by-step explanation:

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Determine if S could lie on the perpendicular bisector of QR with the given coordinates
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Step-by-step explanation:

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