The measure of an inscribed angle in a circle is ______ the measure of the intercepted arc.
1 answer:
C. Half
<u>Explanation:</u>
An inscribed angle is an angle with its vertex on the circle and whose sides are chords. The intercepted arc is the arc that is inside the inscribed angle and whose endpoints are on the angle.
The Inscribed Angle Theorem states that the measure of an inscribed angle is half the measure of its intercepted arc.
Inscribed angles that intercept the same arc are congruent.
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Answer:
A. 3 possible combinations
B. 8 4-ounce's bags and 3 3-ounce's bags
C. 2 4-ounce's bags and 11 3-ounce's bags
D. 8 4-ounce's bags and 3 3-ounce's bags
E. All solutions offer the same revenue.
Step-by-step explanation:
You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy. Let x be the number of 4 ounce bags and y be the number of 3 ounce bags. Then
A. Find all integer solutions:
- When x=0, then 3y=41 - impossible, because 41 is not divisible by 3.
- When x=1, then 3y=37 - impossible, because 37 is not divisible by 3.
- When x=2, then 3y=33, y=11 - possible.
- When x=3, then 3y=29 - impossible, because 29 is not divisible by 3.
- When x=4, then 3y=25 - impossible, because 25 is not divisible by 3.
- When x=5, then 3y=21, y=7 - possible.
- When x=6, then 3y=17 - impossible, because 17 is not divisible by 3.
- When x=7, then 3y=13 - impossible, because 13 is not divisible by 3.
- When x=8, then 3y=9, y=3 - possible.
- When x=9, then 3y=5 - impossible, because 5 is not divisible by 3.
- When x=10, then 3y=1 - impossible, because 1 is not divisible by 3.
You get 3 possible combinations.
B. 1. 2 + 11 = 13,
2. 5 + 7 = 12,
3. 8 + 3 = 11.
The minimal number of bags is 11.
C. 1. 2·7+11·5=69 cents
2. 5·7+7·5=70 cents
3. 8·7+3·5=71 cents
The cheapest is 1st solution.
D. 1. 2·6+11·5=67 cents
2. 5·6+7·5=65 cents
3. 8·6+3·5=63 cents
The cheapest is 3rd solution.
E. 1. 2·2+11·1.50=$20.50
2. 5·2+7·1.50=$20.50
3. 8·2+3·1.50=$20.50
All solutions offer the same revenue.