Question

Two families are shopping for a camping trip. The first family buys 3 flashlights and 4 sleeping bags at a cost of $118. The second family buys 5 flashlights and 6 sleeping bags at a cost of $180. How much does each flashlight and sleeping bag cost?
Let x = the cost of a flashlight

Let y = the cost of a sleeping bag





What is the first equation?


What is the second equation?


What is the cost of a sleeping bag?

Answer 1

Answer:

3x +4y = 118

5x+6y =180

y= $25

Step-by-step explanation:

Let x = the cost of a flashlight

Let y = the cost of a sleeping bag

3x +4y = 118

5x+6y =180

Multiply the first equation by -5

-5(3x +4y) = -5*118

-15x -20y = -590

Multiply the second equation by 3

3(5x+6y) =3*180

15x + 18y = 540

Add the modified equations together.

We are using elimination to eliminate the variable x

-15x -20y = -590

15x + 18y = 540

----------------------------

-2y = -50

Divide by -2

-2y/-2 = -50/-2

y =25

Each sleeping bag costs $25

Answer 2

Answer:

3x +4y = 118

5x+6y =180

25

Step-by-step explanation: