The correct answer would be c
answer: 10/4 reduced is 2.5/1 or 2.5.
work: what we are doing is trying to divide ten into groups of four. how many times does 10 fit into four? well, look at the multiples of four, 4, 8, 12... we can see that 8 fits into ten, but 12 doesn't. that means two whole fours can fit into ten (since 4 x 2 = 8) so we still have a 2 left over from the ten. since 2 is one half of four, we can fit in another .5. so, ten can be fit into 2.5 groups. hope this helps, have a great day!
Since we want it in the form: (x - a)², let's first expand (x - a)² and then equate for the coefficients.
(x - a)² = x² - 2ax + a²
x² + 4x - 15 = x² - 2ax + a²
Now, let's focus on the middle term.
4x = -2ax
4 = -2a
a = -2
Thus, we know that a = -2
Then, we can say (x + 2)² = x² + 4x - 15
x² + 4x + 4 = x² + 4x - 15
Thus, 19 units are needed in order to complete the square to produce:
(x + 2)²
A bisector is a line that divides either a line or an angle into <em>two</em><em> proportionate</em> parts or angles. Thus, Anton's <em>bisector</em> would divide the segment into two <u>equal parts</u>, while Maxim's <em>bisector</em> would divide the angle into two <u>equal angles</u>.
The <u>similarities</u> between their construction are:
- <em>Intersecting</em> arcs through which the bisector would pass are required.
- The arcs are dawn using <em>the same</em> radius of any measure.
- The <em>edges</em> of the arc of the given angle, and the ends of the segment are used as <em>centers</em>.
The <u>differences</u> between their construction are:
- Anton has to draw two intersecting arcs <u>above</u> and <u>below</u> the segment. While Maxim would draw two intersecting arcs <u>within</u> the lines forming the angles.
- Anton's bisector would be <em>perpendicular</em> to the segment, while Maxim's bisector would be at <em>an angle</em> which is half of the initial angle.
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