1) 0.0011 rad/s
2) 7667 m/s
Explanation:
1)
The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:
where
is the angular displacement of the object
t is the time elapsed
is the angular velocity
In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is
rad
And the time taken is
Therefore, the angular velocity of the telescope is
2)
For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation
where
v is the linear velocity
is the angular velocity
r is the radius of the circular orbit
In this problem:
is the angular velocity of the Hubble telescope
The telescope is at an altitude of
h = 600 km
over the Earth's surface, which has a radius of
R = 6370 km
So the actual radius of the Hubble's orbit is
Therefore, the linear velocity of the telescope is:
Answer:
If the ship speed is doubled, then the power developed is 8 times the initial value.
Explanation:
ship power is roughly proportional to the cube of the speed, so
P ∝ v³
If the speed is doubled, then the power developed becomes
P ∝ (2)³ = 8 times
Therefore, if the ship speed is doubled, then the power developed is 8 times the initial value.
1. Define Newtons second law of motion (this will help put things into perspective)
2.Get the mass of the object (in this case 75 kg)
3.The net force acting on the object...find it (in this case 500 N)
4.Change the equation to F=ma (500=75a)
5.Divide both sides by 75 and that is the acceleration.
Answer:
Velocity.
Explanation:
Projectile motion is characterized as the motion that an object undergoes when it is thrown into the air and it is only exposed to acceleration due to gravity.
As per the question, 'any change in the initial velocity of the projectile(object having gravity as the only force) would lead to a change in the range as well as the maximum height of the projectile.' To illustrate numerically:
Horizontal range: As per expression:
R= (
*sin2θ)/g
the range depending on the square of the initial velocity.
Maximum height: As per expression:
H= ( * 
θ
)/2g
the maximum distance also depends upon square of the initial velocity.
Answer:
Option B. magnitude of displacement of a sound pressure wave
Explanation:
Amplitude is simply the maximum displacement of a wave from its mean position.
