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rjkz [21]
3 years ago
12

A box experiencing a gravitational force of 600 N is being pulled to the right with force of 250 N. A 25 N frictional force acts

on the box as it moves to the right.
What is the net force in the y-direction?

0 N
25 N
225 N
250 N
Physics
2 answers:
jeka57 [31]3 years ago
4 0
The answer is: 0 Newtons
gavmur [86]3 years ago
3 0

Answer: (A).The net force in the y-direction will be zero.

Explanation:

Given that,

Gravitational force = 600 N

Frictional force = 25 N

Pulled by the Force = 250 N

We know that,

The gravitational force in downward and normal force act in upward. the frictional force in left side and the box pulled by the force to the right side.

The balance equation is along y-axis

600+N = 0

The box will not move in y-axis therefore, the net force in the y-axis will be zero.

Hence, The net force in the y-direction will be zero.

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Assuming that 70 percent of the Earth’s surface is covered with water at average depth of 0.95 mi, estimate the mass of the wate
Alla [95]

Answer:

The mass of the water on earth is 5.4537\times10^{20}\ kg

Explanation:

Given that,

Average depth h= 0.95 mi

h=0.95\times1.609

h =1.528\ km

h=1.528\times10^{3}\ m

Radius of earth r= 6.37\times10^{6}\ m

Density = 1000 kg/m³

We need to calculate the area of surface

Using formula of area

A =4\pi r^2

Put the value into the formula

A=4\pi\times(6.37\times10^{6})^2

A=5.099\times10^{14}\ m^2

We need to calculate the volume of earth

V = Area\times height

Put the value into the formula

V=5.099\times10^{14}\times1.528\times10^{3}

V=7.791\times10^{17}\ m^3

Now, 70 % volume of the total volume

V= 7.791\times10^{17}\times\dfrac{70}{100}

V=5.4537\times10^{17}\ m^3

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Using formula of density

\rho = \dfrac{m}{V}

m = \rho\times V

Put the value into the formula

m=1000\times5.4537\times10^{17}

m =5.4537\times10^{20}\ kg

Hence, The mass of the water on earth is 5.4537\times10^{20}\ kg

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4 years ago
The weight of a block on the inclined plane is 500 N and the angle of incline is 30 degrees. What is the magnitude of the force
yanalaym [24]

Answer:

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Explanation:

N = Normal force by the surface of the inclined plane

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Parallel to incline, force equation is given as

f = W Sin30

f = (500) Sin30

f = 250 N

Perpendicular to incline force equation is given  

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N = 433 N

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Quantity of electrical charge is measured in Coulombs.

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