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goldenfox [79]
3 years ago
6

A long solenoid that has 1,130 turns uniformly distributed over a length of 0.430 m produces a magnetic field of magnitude 1.00

10-4 T at its center. What current is required in the windings for that to occur?
Physics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Given Information:

Number of turns = N = 1130 turns

Length of solenoid = L = 0.430 m

Magnetic field = B =  1.0x10⁻⁴ T

Required Information:

Current = I = ?

Answer:

I = 0.0302 A

Explanation:

The current flowing in the solenoid winding can be found using

I = BL/μ₀N

Where μ₀ is the permeability of free space, N is the number of turns, B is the magnetic field and L is the length of solenoid

I = 1.0x10⁻⁴*0.430/4πx10⁻⁷ *1130

I = 0.0302 A

or

I = 30.28 mA

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ivanzaharov [21]

Answer:

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We see that we have a positive acceleration and that is what we are going to use in the parabolic motion equations

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Answer:

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4 years ago
When using a series circuit to connect four small light bulbs, which statement is MOST accurate?
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Read 2 more answers
If the ac peak voltage across a 100-ohm resistor is 120 V, then the average power dissipated by the resistor is ________
Kazeer [188]

Answer:

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Explanation:

Given;

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The average power dissipated by the resistor is given by;

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where;

V_{rms} is the root-mean-square-voltage

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The average power dissipated by the resistor is calculated as;

P_{avg} = \frac{V_{rms}^2}{R}\\\\P_{avg} = \frac{84.853^2}{100}\\\\P_{avg} = 72 \ W

Therefore, the average power dissipated is 72 W.

5 0
3 years ago
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