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ohaa [14]
3 years ago
13

Electrons (mass m, charge –e) are accelerated from rest through a potential difference V and are then deflected by a magnetic fi

eld that is perpendicular to their velocity. The radius of the resulting electron trajectory is:
Physics
1 answer:
adell [148]3 years ago
8 0

Answer:

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

Explanation:

Let m and e are the mass and charge of an electron. It is accelerated from rest through a potential difference V and are then deflected by a magnetic field that is perpendicular to their velocity. Let v is the velocity of the electron. It can be calculated as :

\dfrac{1}{2}mv^2=eV

v=\sqrt{\dfrac{2eV}{m}}

When the electron enters the magnetic field, the centripetal force is balanced by the magnetic force as :

\dfrac{mv^2}{r}=evB

r=\dfrac{mv}{eB}

or

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

So, the radius of the resulting electron trajectory is \dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}. Hence, this is the required solution.

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attashe74 [19]

The normal force acting on the object is 500 N in the upward direction

<u>Explanation:</u>

As George is applying a downward force, the normal force will be in the upward direction. The normal force will be exerted due to the acceleration due to gravity exerted on the object.

So, as per Newton's second law, the normal force acting on the object can be measured by the product of mass of the object and the acceleration due to gravity acting on the object.

But as the acceleration due to gravity is a downward acting acceleration and the normal force is a upward acting force, so the acceleration will be having a negative sign in the formula.

Normal\ force = Mass \times Acceleration\ due\ to\ gravity

Here, acceleration due to gravity g = -10 m/s² and mass is given as 50 kg, then

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3 years ago
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Answer:

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Explanation:

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