A rock is thrown horizontally at 10.0m/s off of a 150m sheer cliff. What is the range?
2 answers:
Answer:
55.3 m
Explanation:
First, find how long it takes to land.
Given (in the y direction):
Δy = 150 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
(150 m) = (0 m/s) t + ½ (9.8 m/s²) t²
t = 5.53 s
Given (in the x direction):
v₀ = 10.0 m/s
a = 0 m/s²
t = 5.53 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (10.0 m/s) (5.53 s) + ½ (0 m/s²) (5.53 s)²
Δx = 55.3 m
You might be interested in
costa rica does not have deserts hoped this helped and have a great day:)
Answer:
As force = tension in string so tension in string is 400N
Explanation:
Answer:2 x 10^-5K^-1
Explanation:
The solution is in the attached file
Answer: 140
Explanation: just multiply 7 x 20