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larisa [96]
3 years ago
14

A rock is thrown horizontally at 10.0m/s off of a 150m sheer cliff. What is the range?

Physics
2 answers:
inn [45]3 years ago
7 0

Answer:20

Explanation:

sattari [20]3 years ago
3 0

Answer:

55.3 m

Explanation:

First, find how long it takes to land.

Given (in the y direction):

Δy = 150 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(150 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 5.53 s

Given (in the x direction):

v₀ = 10.0 m/s

a = 0 m/s²

t = 5.53 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (10.0 m/s) (5.53 s) + ½ (0 m/s²) (5.53 s)²

Δx = 55.3 m

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Explanation:

The given data is as follows.

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After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

                 \sum M_{o} = 0

     -W_{s} \times x + W_{b} \times 1.5 = 0

                x = \frac{W_{b} \times 1.5}{W_{s}}

                   = \frac{332 N \times 1.5}{505 N}

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Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.

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Answer:

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Now we have given the above information and from the given distance function, we have to find the SI units of the A and B. Here, below are the SI units.

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