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DedPeter [7]
3 years ago
11

Which of the following best describes what went wrong with the scientists’ study? an improper experimental procedure the lack of

a control group selection bias human error
Physics
2 answers:
Mars2501 [29]3 years ago
7 0

Newton Calculation Error

in the book "Principia Mathematica" contains a simple calculation error that was not discovered for 300 years. Errors occur in Proposition Eight, where Newton presents a formula for calculating the mass of the planet, involving angles formed by two specific lines.

<h2>Further explanation </h2>

<em>The mistakes made by scientists: </em>

<h3>Galileo's Tidal Theories </h3>

He was wrong from the start, starting his efforts to explain the tidal movements with a false premise - namely that it was caused by the rotation of the earth around the sun. This means the theory is incorrect because it is based on mistakes.

<h3>Darwin and the Theory of Heredity </h3>

One problem with Darwin's original theory concerns heredity. Many people have a misconception about how characteristics are passed down from parents to their children. The problem is that this notion of mixed genetics contradicts Darwin's own theory. If that is true, then the characteristics will not change from generation to generation through natural selection.

<h3>Triple helix from Linus Pauling </h3>

Despite getting the Nobel Prize, Pauling admitted there was an error in his discovery. The model is wrong for a very simple reason: This includes the triple helix. He also made a basic mistake in his calculations, and the nucleic acid molecule in his model was actually not acidic.

<h3>Edwin Hubble's Universe Calculations </h3>

According to Hubble, the universe is two billion years old. This statement is proven wrong. In the 1930s, a study said the earth was between three and five billion years old. Obviously, our planet cannot be older than the universe, so something's wrong with Hubble.

Learn More

Scientist brainly.com/question/6701391

The Mistakes from Scientist brainly.com/question/6701391

Details

Class: High School

Subject: Physics

Keywords: scientist, mistake, newton

Rasek [7]3 years ago
3 0
B- lack of control.

the scientists did not have a proper control group.
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Answer:

The focal length of eye piece is 6.52 cm.

Explanation:

Given that,

Angular Magnification of the microscope M = -46

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The focal length of objective f₀ = 1.5 cm

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Have to find focal length of eye piece f ₙ =?

The angular magnification is given by

M ≈ - (L-fₙ)N/f₀fₙ

Rearranging for fₙ

fₙ =L(1 - Mf₀/N)⁺¹

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A block weighting 400kg rests on a horizontal surface and support on top of it another block of weight 100kg placed on the top o
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The horizontal force applied to the block is approximately 1,420.84 N

The known parameters;

The mass of the block, w₁ = 400 kg

The orientation of the surface on which the block rest, w₁ = Horizontal

The mass of the block placed on top of the 400 kg block, w₂ = 100 kg

The length of the string to which the block w₂ is attached, l = 6 m

The coefficient of friction between the surface, μ = 0.25

The state of the system of blocks and applied force = Equilibrium

Strategy;

Calculate the forces acting on the blocks and string

The weight of the block, W₁ = 400 kg × 9.81 m/s² = 3,924 N

The weight of the block, W₂ = 100 kg × 9.81 m/s² = 981 N

Let <em>T</em> represent the tension in the string

The upward force from the string = T × sin(θ)

sin(θ) = √(6² - 5²)/6

Therefore;

The upward force from the string = T×√(6² - 5²)/6

The frictional force = (W₂ - The upward force from the string) × μ

The frictional force, F_{f2} = (981 - T×√(6² - 5²)/6) × 0.25

The tension in the string, T = F_{f2} × cos(θ)

∴ T = (981 - T×√(6² - 5²)/6) × 0.25 × 5/6

Solving, we get;

T = \dfrac{5886}{\sqrt{6^2 - 5^2} + 28.8} \approx 183.27

Frictional \ force, F_{f2} = \left (981 -  \dfrac{5886}{\sqrt{6^2 - 5^2} + 28.8}  \times \dfrac{\sqrt{6^2 - 5^2} }{6} \times  0.25 \right) \approx 219.92

The frictional force on the block W₂, F_{f2} ≈ 219.92 N

Therefore;

The force acting the block w₁, due to w₂ F_{w2} = 219.92/0.25 ≈ 879.68

The total normal force acting on the ground, N = W₁ + \mathbf{F_{w2}}

The frictional force from the ground, \mathbf{F_{f1}} = N×μ + \mathbf{F_{f2}} = P

Where;

P = The horizontal force applied to the block

P = (W₁ + \mathbf{F_{w2}}) × μ + \mathbf{F_{f2}}

Therefore;

P = (3,924 + 879.68) × 0.25 + 219.92 ≈ 1,420.84

The horizontal force applied to the block, P ≈ 1,420.84 N

Learn more about friction force here;

brainly.com/question/18038995

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Answer:

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