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PilotLPTM [1.2K]
1 year ago
10

True or FalseIf an object is submerged in water, on earth, at a depth of 3km, the Pressure on the object is2.94 x 10^7 Pa

Physics
1 answer:
zhenek [66]1 year ago
6 0

The pressure of a submerged object in a fluid is given by:

P=\rho gh+P_{atm}

where ρ is the density of the fluis, g is the acceleration of gravity, h is the depth of the object and Patm is the pressure of the atmosphere. In this case we know that:

• The density of water is 1000 kg/m^3

,

• The acceleration of gravity is 9.8 m/s^2

,

• The depth of the object is 3 km, that is, 3000 m.

,

• The atmospheric pressure is 101325 pascals.

Plugging these values in the equation given above we have:

\begin{gathered} P=(1000)(9.8)(3000)+101325 \\ P=2.95\times10^7 \end{gathered}

Therefore, the pressure at this depth is 2.95x10^7 Pa.

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Breh seriously. Ugh fine.

1.B

2.D

3.C

4.C

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Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​
gtnhenbr [62]

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The given resistors are:

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The net resistance will be:

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On substituting the values, we get

⇒  \frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}

On taking L.C.M, we get

⇒  \frac{1}{R_{net}} =\frac{2+1}{6}

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Wd = 22.9 × 129 × 0.8192

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Thus, the workdone is 2420 J.

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