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PilotLPTM [1.2K]
1 year ago
10

True or FalseIf an object is submerged in water, on earth, at a depth of 3km, the Pressure on the object is2.94 x 10^7 Pa

Physics
1 answer:
zhenek [66]1 year ago
6 0

The pressure of a submerged object in a fluid is given by:

P=\rho gh+P_{atm}

where ρ is the density of the fluis, g is the acceleration of gravity, h is the depth of the object and Patm is the pressure of the atmosphere. In this case we know that:

• The density of water is 1000 kg/m^3

,

• The acceleration of gravity is 9.8 m/s^2

,

• The depth of the object is 3 km, that is, 3000 m.

,

• The atmospheric pressure is 101325 pascals.

Plugging these values in the equation given above we have:

\begin{gathered} P=(1000)(9.8)(3000)+101325 \\ P=2.95\times10^7 \end{gathered}

Therefore, the pressure at this depth is 2.95x10^7 Pa.

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Answer: Leandra puts on her mittens because if you do not you will burn your self, due to extremely high temperatures.

Explanation:

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The mass of a truck with its cargo is 1800 kg. The truck is coasting to the right with a speed of 10 m/s. As it coasts its cargo
OverLord2011 [107]

Here we apply conservation of linear momentum. The momentum of the truck with cargo and without cargo remains constant. That is,

mv=m'v'.

Here m,v are initial mass and velocity. m',v' are final mass and velocity. Here m=1800,v=10 and m'=1800-300=1500.

The velocity of the truck be after its cargo is taken off is

v'=\frac{mv}{m'} \\  v'=\frac{1800*10}{1500} \\  v'=12 m/s

6 0
4 years ago
Read 2 more answers
An automobile engine delivers 47.4 hp. how much time will it take for the engine to do 6.82 × 105 j of work? one horsepower is e
kogti [31]
1 horsepower is equal to 746 W, so the power of the engine is
P=47.4 hp \cdot 746  \frac{W}{hp}=35360 W
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P= \frac{E}{t}
Where the energy corresponds to the work done by the engine, which is E=6.82 \cdot 10^5 J. Re-arranging the formula, we can calculate the time t needed to do this amount of work:
t =  \frac{E}{P}= \frac{6.82 \cdot 10^5 J}{35360 W}=19.3 s
8 0
3 years ago
Accomplished silver workers in india can pound silver into incredibly thin sheets, as thin as 3.00 10-7 m (about one-hundredth o
postnew [5]
The density of silver is ρ = 10500 kg/m³ approximately.

Given:
m = 1.70 kg, the mass of silver
t = 3.0 x 10⁻⁷ m, the thickness of the sheet

Let A be the area.
Then, by definition,
m = (t*A)*ρ

Therefore
A = m/(t*ρ)
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Answer: 539.7 m²

8 0
3 years ago
Pls help with these two last questions
zhenek [66]

Answer:

F = 50[N], to the left.

v = 10.52 [m/s]

Explanation:

<u>First problem</u>

<u />

In order to solve this problem we must apply Newton's laws, in such a way that we must perform a summation of forces on the horizontal axis. In this way we will analyze each force and the direction of action.

The offensive player is applying a force of 100N to the right, while the defensive player applies a force of 150N to the left. In this way performing the summation of forces we have.

100 - 150 = F

F = - 50 [N]

Note: The negative sign indicates that the resulting force is to the left.

<u>Second problem</u>

<u />

We must remember that the definition of speed is equal to the relationship between distance over time.

x = distance = 100 [m]

t = time = 9.5 [s]

v = x/t

v = 100/9.5

v = 10.52 [m/s]

<u />

5 0
4 years ago
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