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Alecsey [184]
3 years ago
9

How many elements are in an m x n matrix?

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
5 0

Answer: m X n matrix contains mn elements

Step-by-step explanation:

You might be interested in
According to a college survey, 22% of all students work full time. Find the standard deviation for the random variable X, the nu
mixer [17]

Answer:

1.66

Step-by-step explanation:

Calculation to find the standard deviation for the random variable X of the number of students who work full time in samples of size

Using this formula

Standard deviation(X)=√np(1−p)

Where,

n represent the number of students=16

p represent the percentage of all students who work full time=22

Let plug in the formula

Standard deviation(X)=√16(0.22)(1−0.22)

Standard deviation(X)=√(3.52)(0.78)

Standard deviation(X)=√2.7456

Standard deviation(X)=1.656

Standard deviation(X)=1.66 (Approximately)

Therefore the standard deviation for the number of students who work full time in samples of size 16 will be 1.66

8 0
3 years ago
Based on the pattern in the table what is the value of A
Arlecino [84]
Answer D, 1/64

The denominator has a pattern , if you look through it carefully each denominator is multiply by 2. There for you multiply 32 x 2 which gives you 64 so it’s 1/64. If you wanna confirm it , you could use a calculator to check your answer.


5 0
3 years ago
Read 2 more answers
Please say me the answer fast and correct.... ​
Kruka [31]

Answer:

i dont know lol

3 0
3 years ago
Triangle abc is translated 5 units to the right and 4 units up to create triangle A’B’C .
eimsori [14]

Answer:

This cannot be solved unless I have the coordinate for triangle "abc"

Step-by-step explanation:

Once I have the coordinates for triangle "abc", I can solve to find out where triangle "A'B'C" is

8 0
2 years ago
The average of your first 6 tests is 82. If your test average after your seventh test is an 80.5, what did you score on the seve
mart [117]
So average is  of the first 6 tests is 82   well that means 

(test1 + test2+ test3+ test4 + test5+test6)/6 = 82

so now let do some cross multiplliying 

test1 + test2 + test3 + test 4 + test5 +test6 = 82*6

test1 + test2 + test3 + test 4 + test5 +test6  = 492

now lets see if we can find that 7th test score

(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5

So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute. 

(492 + test7 )/7 = 80.5

test7 = (80.5*7)-492 = 71.5 



7 0
3 years ago
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