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aleksklad [387]

2 years ago

9

to travel at a constant velocity, a car exerts force that is 551N to balance air resistance. how much work does the car do on th

e air as it tavels 161km from columbus to to cincinatti

1 answer:

densk [106]2 years ago

7 0

Answer:88711000joules

Explanation:

Firstly we have to convert 161km to meters

161km=161×1000m=161000m

Work=force×distance

Work=551×161000

Work=88711000joules

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Five identical quintuplets leave earth when they reach the age of 21, in the year 2121. Each quintuplet goes on a spaceship jour

Elena-2011 [213]

Answer:

Explanation:

This is a problem based on time dilation , a theory given by Albert Einstein .

The formula of time dilation is as follows .

t₁ = $\frac{t}{\sqrt{1-\frac{v^2}{c^2} } }$

t is time measured on the earth and t₁ is time measured by man on ship .

A ) Given t = 20 years , t₁ = ? v = .4c

$\frac{20}{\sqrt{1-\frac{.16c^2}{c^2} } }$

=1.09 x 20

t₁= 21.82 years

B ) Given t = 5 years , t₁ = ? v = .2c

$\frac{5}{\sqrt{1-\frac{.04c^2}{c^2} } }$

=1.02 x 5

t₁= 5.1 years

C ) Given t = 10 years , t₁ = ? v = .8c

$\frac{10}{\sqrt{1-\frac{.64c^2}{c^2} } }$

=1.67 x 10

t₁= 16.7 years

D ) Given t = 10 years , t₁ = ? v = .4c

$\frac{10}{\sqrt{1-\frac{.16c^2}{c^2} } }$

=1.09 x 10

t₁= 10.9 years

E ) Given t = 20 years , t₁ = ? v = .8c

$\frac{20}{\sqrt{1-\frac{.64c^2}{c^2} } }$

=1.67 x 20

t₁= 33.4 years

7 0

2 years ago

uppose two train cars are moving toward one another, the first with a mass of 150,000 kg and a velocity of 0.300 m/s; the second

kondaur [170]

The value was determined to be 0.122 m/s. The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form.

Velocity is essentially a vector quantity. It is the rate of change in distance. The initial speed of the first train, which has a mass of 150,000 kg, is 0.3 m/s. The second train has an initial speed of -0.120 m/s and a mass of 110,000 kg.

Let v represent the post-collision speed of the connected mass.

Utilize the idea of momentum.

The speed of the trains is constant both before and after a collision.

150.000 + 110.000v 45.000 - 13200 = 260.000 v 31800 = 260.000 v v = 0.122 m/s 150000 x 0.3 - 110000 x 0.120

After colliding, they move at a speed of 0.122 m/s towards the direction of the right.

Learn more about velocity here-

brainly.com/question/18084516

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7 0

8 months ago

Alexxx [7]

The force constant of the spring is determined as 14,222.2 N/m.

<h3>Force constant of the spring</h3>

Apply the principle of conservation of energy,

K.E = U

where;

K.E kinetic energy of the elevator
U is elastic potential energy of the spring

¹/₂mv² = ¹/₂kx²

mv² = kx²

k = mv²/x²

Where;

m is mass of the elevator
v is speed
x is compression of the spring

k = (2000 x 8²)/(3²)

k = 14,222.2 N/m

Thus, the force constant of the spring is determined as 14,222.2 N/m.

Learn more about force constant here: brainly.com/question/1968517

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5 0

1 year ago

Laboratory experiments here on Earth have determined that each element in the periodic table emits photons only at certain wavel

elena-14-01-66 [18.8K]

The only thing we know about so far that can shift wavelengths of light
to longer wavelengths is when the source of the light is moving away
from the observer.

When we look at the light from distant galaxies, the light from them is
always shifted to longer wavelengths than it SHOULD have.

AND ... The farther away from us a galaxy IS, the MORE its light is
shifted to wavelengths longer than it should have.

So far, this indicates to us that the whole universe is expanding.
That's the only way to understand what we see, because that's
the only thing we know of that can shift light to longer wavelengths.

By the way ... The most interesting thing about these observations
and measurements is: When astronomers see this light from distant
galaxies and measure the wavelengths, how do they know how far
the wavelengths shifted ? How do they know what the wavelengths
SHOULD be ?

I'll leave you to read about that in the next few years.

7 0

3 years ago

During typical urination, a man releases about 400 mL of urine in about 30 seconds through the urethra, which we can model as a

gregori [183]

Answer:

Explanation:

Given:

volume of urine discharged, $V=400~mL=0.4~L=4\times 10^{-4}~m^3$

time taken for the discharge, $t=30~s$

diameter of cylindrical urethra, $d=4\times10^{-3}~m$

length of cylindrical urethra, $l=0.2~m$

density of urine, $\rho=1000~kg/m^3$

a)

we have volume flow rate Q:

$Q=A.v$ & $Q=\frac{V}{t}$

where:

$A=$ cross-sectional area of urethra

$v=$ velocity of flow

$A.v=\frac{V}{t}$

$\frac{\pi d^2}{4}\times v=\frac{4\times 10^{-4}}{30}$

$v=\frac{4\times4\times 10^{-4}}{30\times \pi (4\times 10^{-3})^2}$

$v=1.06~m/s$

b)

The pressure required when the fluid is released at the same height as the bladder and that the fluid is at rest in the bladder:

$P=\rho.g.l$

$P=1000\times 9.8\times 0.2$

$P=1960~Pa$

5 0

3 years ago