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3 years ago

A.

Physics

1 answer:

V125BC [204]3 years ago

7 0

Answer:

All the planets orbit the Sun in nearly the same plane.

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When mantle rocks near the radioactive core are heated, they become less dense than the cooler, upper mantle rocks. These warmer

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C.convection cells is the right answer

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3 years ago

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In a police ballistics test, 2.00-g bullet traveling at 700 m/s suddenly hits and becomes embedded in a stationary 5.00-kg wood

aksik [14]

Answer:

Here we use the conservation of momentum theorem.

m stands for mass, and v stands for velocity. The numbers refer to the respective objects.

m1v1 + m2v2 = m1vf1 + m2vf2

Since the equation is perfectly inelastic, the final velocity of both masses is the same. Let’s account for this in our formula.

m1v1 + m2v2 = vf(m1 + m2)

<u>Let’s substitute in our givens.</u>

(0.002 kg)(700 m/s) + (5 kg)(0 m/s) = vf(0.002 kg + 5 kg)

I assume you are proficient in algebra I, so I will not include the steps to simplify this equation.

Note that I have considered the bullet’s velocity to be in the positive direction,

The answer is vf = 0.280 m/s

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3 years ago

Which of the following describes how a sound wave can bounce off a surface?

Gennadij [26K]

Answer:

Explanation:

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3 years ago

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A ball is dropped from a rooftop 60m high. <br> How long is the ball in the air?

alina1380 [7]

Answer: 3.49 s

Explanation:

We can solve this problem with the following equation of motion:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0 m$ is the final height of the ball

$y_{o}=60 m$ is the initial height of the ball

$V_{o}=0 m/s$ is the initial velocity (the ball was dropped)

$g=9.8 m/s^{2}$ is the acceleratio due gravity

$t$ is the time

Isolating $t$ :

$t=\sqrt{\frac{2 y_{o}}{g}}$ (2)

$t=\sqrt{\frac{2 (60 m)}{9.8 m/s^{2}}}$ (3)

Finally we find the time the ball is in the air:

$t=3.49 s$ (4)

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4 years ago

A 1100 kg car is traveling around a flat 82.3 m radius curve. The coefficient of static friction between the car tires and the r

Novay_Z [31]

Answer:

The maximum speed of car will be 20.5m/sec

Explanation:

We have given mass of car = 1100 kg

Radius of curve = 82.3 m

Static friction $\mu _s=0.521$

We have to find the maximum speed of car

We know that at maximum speed centripetal force will be equal to frictional force $m\frac{v^2}{r}=\mu _srg$

$v=\sqrt{\mu _srg}=\sqrt{0.521\times 82.3\times 9.8}=20.5m/sec$

So the maximum speed of car will be 20.5m/sec

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3 years ago

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