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Kamila [148]
3 years ago
13

A resistor is made by winding a very long thin metal wire, insulated so adjacent coils do not touch. At room temperature, the re

sistance is 100 ohms.
If the resistor is then cooled to 77 K, the resistance:

A. changes only slightly, if at all.
B. increases significantly (more than a factor of two).
C. decreases significantly (more than a factor of 1/2).
Physics
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer:

Option A

Explanation:

The correct answer is  Option A.

At room temperature, the resistance is equal to 100 ohms.

When the temperature is reduced to 77 K from room temperature, change in the resistance is very less.

The temperature coefficient of the resistivity of most of the metal is small for the metals which are approximately equal  0.01 /K.

hence, Change is only slightly.

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A certain planet has a radius of 4990 km. If, on the surface of that planet, a 95.0 kg object has a weight of 591 N, then what i
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3743.489 kg

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F_g = 591 N

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7 0
4 years ago
An object carries a +15.5 uC charge.
abruzzese [7]

Answer:

3.67 N

Explanation:

From the question given above, the following data were obtained:

Charge of 1st object (q₁) = +15.5 μC

Charge of 2nd object (q₂) = –7.25 μC

Distance apart (r) = 0.525 m

Force (F) =?

Next, we shall convert micro coulomb (μC) to coulomb (C). This can be obtained as follow:

For the 1st object

1 μC = 1×10¯⁶ C

Therefore,

15.5 μC = 15.5 × 1×10¯⁶

15.5 μC = 15.5×10¯⁶ C

For the 2nd object:

1 μC = 1×10¯⁶ C

Therefore,

–7.25 μC = –7.25 × 1×10¯⁶

–7.25 μC = –7.25×10¯⁶ C

Finally, we shall determine the force. This can be obtained as follow:

Charge of 1st object (q₁) = +15.5×10¯⁶ C

Charge of 2nd object (q₂) = –7.25×10¯⁶ C

Distance apart (r) = 0.525 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

F = Kq₁q₂ / r²

F = 9×10⁹ × 15.5×10¯⁶ × 7.25×10¯⁶ / 0.525²

F = 3.67 N

Therefore, the force on the object is 3.67 N

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