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Vesnalui [34]
3 years ago
14

Help!!! Pleaaaaaseee SOS!!

Physics
1 answer:
OLga [1]3 years ago
7 0

Answer:

D. When its weight is equal to the buoyant force exerted by the water.

Explanation:

A fluid exerts an upward force on a body submerged in it. This force that tends to lift the body is called floating force.

The flotation force that acts on a body submerged in a fluid is equal  to the weight of the fluid displaced by the body and acts upward passing through the centroid of the displacemented volume.

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Aristotle believed that matter was
lbvjy [14]

Answer:

Aristotle believed that matter was made of tiny particles.

Explanation:

''Aristotle vehemently opposed the Atomic theory developed by Democritus. He believed that instead of being matter being made of tiny particles (atoms) that they were all fundamentally air, fire, water, and earth.''

8 0
3 years ago
Read 2 more answers
Suppose a skydiver (mass =100kg) is falling towards the earth. When the skydiver is 80 m above the earth he is moving at 60 m/s
goblinko [34]

Answer:

The total mechanical energy of the skydiver is, E  = 96402.6 J

Explanation:

Given data,

The mass of the skydiver, m = 100 kg

The speed of the skydiver at 80 m height, v = 60 m/s

The initial velocity of the skydiver, u = 0

Using the III equations of motion,

                                  v² = u² + 2gs

                                   s = v²/2g

Substituting the given values,

                                   s = ½ 60²/ 9.8

                                      = 18.37 m

Hence the initial total distance of the skydiver from the ground initially,

                                    h = s + d

                                        = 18.37 + 80

                                         = 98.37 m

Since the total mechanical energy of a system is conserved, the total mechanical energy of the skydiver at height 'h' is equal to the total mechanical energy at height 'd'.

                                        E = P.E + K.E

                                            = mgh + ½ mu²

                                            = 100 x 9.8 x 98.37     ( ∵ u = 0)

                                             = 96402.6 J

Hence, the total mechanical energy of the skydiver is, E  = 96402.6 J

5 0
3 years ago
Two long, parallel wires are attracted to each other by a force per unit length of 305 µN/m. One wire carries a current of 25.0
kykrilka [37]

To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:

\frac{F}{L} = \frac{kl_1l_2}{d}

Here,

F = Force

L = Length

k = Coulomb constant

I =Each current

d = Distance

Force of the wire one which is located along the line y to 0.47m is 305*10^{-6}N/m then we have

l_2 = \frac{F}{L} (\frac{d}{kl_1})

l_2 = (305*10^{-6}N/m)(\frac{0.470m}{(2*10^{-7})(25A))})

l_2 = 28.67A

Considering the B is zero at

y = y_1

\frac{kI_2}{2\pi y} =\frac{kI_1}{2\pi y_1}

\frac{(4\pi*10^{-7})(28.67)}{2\pi (y_1)} = \frac{(4\pi *10^{-7})(25)}{2\pi (0.47-y_1)}

y_1 = 0.25m

Therefore the value of y for the line in the plane of the two wires along which the total B is zero is 0.25m

5 0
4 years ago
I can’t figure this out!!! Answer what you can , please.
tigry1 [53]

a/b. The ball has velocity vector at time t

\vec v=(v_x,v_y)=(v_0\cos63^\circ,v_0\sin63^\circ-gt)

where v_0=16\dfrac{\rm m}{\rm s} is the ball's initial speed and g=9.8\dfrac{\rm m}{\mathrm s^2}.

c. At its highest point, the ball has 0 vertical speed. This occurs when

v_0\sin63^\circ-gt=0\implies t=1.5\,\mathrm s

d. Recall that

{v_y}^2-{v_{0y}}^2=-2g\Delta y

so that at its highest point,

0^2-(v_0\sin63^\circ)^2=-2g\Delta y\implies\Delta y=10\,\mathrm m

e. This is just twice the time it takes for the ball to reach its maximum height, t=2.9\,\mathrm s.

f. The ball's horizontal position after time t is

v_0\cos63^\circ\,t

so that after the time found in part (f), the ball has traveled

v_0\cos63^\circ(2.9\,\mathrm s)=11\,\mathrm m

4 0
4 years ago
A body has a mass of 2kg.it accelerats from 20m/s to 40m/s in 4 seconds.the resultant force is<br>​
GaryK [48]

The resultant force is 8N  

Given that mass is 2kg , v= 40m/s, u =20m/s and we need to calculate resultant force
F=ma

m is given
so for a
v-u/t=a { first equation of motion }

40-20/4= 4
so a=4

F = ma =2*4 = 8N
The difference between the forces that are acting on an object as part of a system is known as the resultant force.
v = u + at is the first equation of motion. Here, v denotes the end speed, u the starting speed, an acceleration, and t the passage of time. The first equation of motion is provided by the velocity-time relation, which may be used to calculate acceleration.

To learn more about resultant force please visit -
brainly.com/question/22260425
#SPJ1

8 0
2 years ago
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