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Vesnalui [34]
3 years ago
14

Help!!! Pleaaaaaseee SOS!!

Physics
1 answer:
OLga [1]3 years ago
7 0

Answer:

D. When its weight is equal to the buoyant force exerted by the water.

Explanation:

A fluid exerts an upward force on a body submerged in it. This force that tends to lift the body is called floating force.

The flotation force that acts on a body submerged in a fluid is equal  to the weight of the fluid displaced by the body and acts upward passing through the centroid of the displacemented volume.

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Need help 14 points
valentinak56 [21]
Biological adaptation
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3 years ago
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A laser is placed at the point $(3,5)$. The laser beam travels in a straight line. Larry wants the beam to hit and bounce off th
Black_prince [1.1K]

Answer:

4units

Explanation:

To calculate the total distance the beam will travel along this path, you will use the formula for calculating the distance between two coordinates expressed as;

D = √(x2-x1)²+(y2-y1)²

Given the coordinate points

(3,5) and (7,5)

Substitute

D = √(7-3)²+(5-5)²

D = √(7-3)²+0²

D = √4²

D = √16

D = 4

Hence the total distance the beam will travel along this path is 4units

6 0
3 years ago
Given a force of 100 N and an acceleration of 10 m/s^2, what is the mass?
frutty [35]

Given:

Force(F): 100 N

Acceleration: 10 m/s^2

Now we know that

F= mx a

Where F is the force acting on the object which is measured in Newton

m is the mass of the object measured in Kg

a is the acceleration measured in m/s^2

Substituting the given values in the above formula we get

100= 10m

m= 10 Kg

6 0
4 years ago
Read 2 more answers
The fixed point that a lever pivots around is the ?
dezoksy [38]
The fixed the the lever pivots around is called the fulcrum
5 0
3 years ago
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A small remote controlled car with mass 1.60 kg moves at a constant speed of12.0 m/s in a vertical circle with a radius of 5.0 m
kenny6666 [7]

Answer:

61.76 N.

Explanation:

Given the mass of the car, m = 1.60 kg.

The speed of the car, v = 12.0 m/s.

The radius of the circle, r = 5 m.

As car is moving in circular motion, so net force ( normal force + weight of the car) is equal to centripetal force enables the car to reamins in circular path.

Let N is the normal force.

So, N - mg = F_c

N-mg=\frac{mv^2}{r}

Now substitute the given values, we get

N-1.60kg\times9.8m/s^2=\frac{1.60kg\times(12.0m/s)^2}{5.0m}

N=15.68+46.08

N = 61.76  N.

Thus, the magnitude ofthe normal force exerted on the car by the walls is 61.76 N.

5 0
3 years ago
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