Answer:
4units
Explanation:
To calculate the total distance the beam will travel along this path, you will use the formula for calculating the distance between two coordinates expressed as;
D = √(x2-x1)²+(y2-y1)²
Given the coordinate points
(3,5) and (7,5)
Substitute
D = √(7-3)²+(5-5)²
D = √(7-3)²+0²
D = √4²
D = √16
D = 4
Hence the total distance the beam will travel along this path is 4units
Given:
Force(F): 100 N
Acceleration: 10 m/s^2
Now we know that
F= mx a
Where F is the force acting on the object which is measured in Newton
m is the mass of the object measured in Kg
a is the acceleration measured in m/s^2
Substituting the given values in the above formula we get
100= 10m
m= 10 Kg
The fixed the the lever pivots around is called the fulcrum
Answer:
61.76 N.
Explanation:
Given the mass of the car, m = 1.60 kg.
The speed of the car, v = 12.0 m/s.
The radius of the circle, r = 5 m.
As car is moving in circular motion, so net force ( normal force + weight of the car) is equal to centripetal force enables the car to reamins in circular path.
Let N is the normal force.
So, 
Now substitute the given values, we get
N = 61.76 N.
Thus, the magnitude ofthe normal force exerted on the car by the walls is 61.76 N.
