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2 years ago

During a chemical reaction, the amount of energy (2 points)

Chemistry

1 answer:

andreyandreev [35.5K]2 years ago

6 0

Answer is b your welcome

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What is the volume of 2.0 mol CO2 at STP?

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Answer:

44.8 litres is the answer to the question

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2 years ago

A student wants to make a 0.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle containing 12.00 g of barium sulfa

love history [14]

Answer: The volume of the solution is 85.7 mL

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}$ .....(1)

We are given:

Molarity of solution = 0.600 M

Given mass of $BaSO_4$ = 12.00 g

We know, molar mass of $BaSO_4=[(1\times 137.33)+(1\times 32.07)+(4\times 16)]=233.4g/mol$

Putting values in equation 1, we get:

$0.600=\frac{12.00\times 1000}{233.4\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{12.00\times 1000}{233.4\times 0.600}=85.68mL=85.7mL$

The rule of significant number that is applied for the problems having multiplication and division:

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.

Hence, the volume of the solution is 85.7 mL

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2 years ago

The law of conservation of matter states that matter cannot be created or destroyed. This law applies when a chemical change occ

lora16 [44]

It says it will never change. So whatever it was before the change, it will be the same after the change. So, 200 should be correct.

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2 years ago

What is the mass of 0.73 moles of AgNO3?

love history [14]

Answer:

124 g (3 sig figs)

124.011 g (6 sig figs

Explanation:

Step 1: Calculate g/mol for AgNO₃

Ag - 107.868 g/mol

N - 14.01 g/mol

O - 16.00 g/mol

107.868 + 14.01 + 16.00(3) = 169.878 g/mol

Step 2: Multiply 0.73 moles by molar mass

0.73 mol (169.979 g/mol)

124 grams of AgNO₃

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2 years ago

What is the formula mass of ethyl alcohol, C2H5OH

Fofino [41]

46.06844 g/mol
yup
yup
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2 years ago