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valentina_108 [34]
3 years ago
11

Why is it difficult for hydrogen atoms to stick together

Chemistry
1 answer:
Rasek [7]3 years ago
6 0

Answer:

So, the energy of two hydrogen atoms is lower when the two atoms are together than when the two atoms are apart; that is why they stay together.

Explanation:

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Material from an environmental study was suspected to contain the banned pesticide, Aldrin, of which you have a pure sample. Gas
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In order  to determine unequivocally which of the peaks represent Aldrin, I would run the pure sample through the chromatography equipment.

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The _______ gives the smallest whole number ratio of moles of each element in a compound. therefore, multiple compounds may have
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The <u>Empirical formula</u> gives the smallest whole number ratio of moles of each element in a compound. therefore, multiple compounds may have it in common.

<h3>What is Empirical formula?</h3>

The most straightforward whole number ratio of atoms in a compound is its empirical formula. The empirical formula for sulfur monoxide, or SO, and disulfur dioxide, or S2O2, are both straightforward illustrations of this idea.

<h3>What is multiple compounds?</h3>

According to the law of multiple proportions, if two elements combine to form more than one compound, the ratio of the second element's mass to the fixed mass of the first element will always be a ratio of tiny whole numbers.

<h3>What is empirical formula used for?</h3>

Typically, the empirical formula is used to simply display the components of a molecule. When one needs to quickly identify the elements they are working with, this is helpful. When you want to know how many atoms of each element are present in the molecule, the molecular formula is most helpful.

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Androstenedione, which contains only carbon, hydrogen, and oxygen, is a steroid hormone produced in the adrenal glands and the g
Gennadij [26K]

Answer: The molecular formula for androstenedione is, C_{19}H_{26}O_2

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=5.527g

Mass of H_2O=1.548g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 5.527 g of carbon dioxide, \frac{12}{44}\times 5.527=1.507g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.548 g of water, \frac{2}{18}\times 1.548=0.172g of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (1.893g)-[(1.507g)+(0.172g)]=0.214g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.507g}{12g/mole}=0.126moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.172g}{1g/mole}=0.172moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.214g}{16g/mole}=0.0133moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0133 moles.

For Carbon = \frac{0.126}{0.0133}=9.5

For Hydrogen  = \frac{0.172}{0.0133}=12.9\approx 13

For Oxygen  = \frac{0.0133}{0.0133}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 9.5 : 13 : 1

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of C : H : O = 19 : 26 : 2

Thus, the empirical formula for the given compound is C_{19}H_{26}O_2

The empirical formula weight of C_{19}H_{26}O_2 = 19(12) + 26(1) + 2(16) = 286 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{286.4}{286}=1

Molecular formula = C_{19}H_{26}O_2

Therefore, the molecular formula for androstenedione is, C_{19}H_{26}O_2

3 0
3 years ago
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