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3 years ago

13

What is a time machine? who discovered the time machine

1 answer:

o-na [289]3 years ago

6 0

<em>A</em><em> </em><em>time</em><em> </em><em>machine</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>device</em><em> </em><em>which </em><em>can</em><em> </em><em>transport </em><em>an</em><em> </em><em>object</em><em> </em><em>or</em><em> </em><em>person</em><em> </em><em>back</em><em> </em><em>in</em><em> </em><em>time</em><em> </em><em>or</em><em> </em><em>in</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>future</em><em>.</em><em> </em>

<em>Ali</em><em> </em><em>Razeghi</em><em> </em><em>is </em><em>the </em><em>person </em><em>who </em><em>invented</em><em> </em><em>the</em><em> </em><em>time</em><em> </em><em>machine</em><em>.</em>

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For every 2 moles of CO and 1 mole of O2, 2 moles of CO2 will be produced.

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Perform the following

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the spectral lines observed for hydrogen arise from transitions from excited states back to the n=2 principle quantum level. Cal

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Rydberg formula is given by:

$\frac{1}{\lambda } = R_{H}\times (\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} )$

where, $R_{H}$ = Rydberg constant = $1.0973731568508 \times 10^{7} per metre$

$\lambda$ = wavelength

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Now, for $n_{1}$ = 2 and $n_{2}$ = 6

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{6^{2}} )$

= $1.0973731568508 \times 10^{7} \times (\frac{1}{4}-\frac{1}{36} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.0278 )$

= $1.0973731568508 \times 10^{7} \times 0.23$

= $0.2523958\times 10^{7}$

$\lambda = \frac{1}{0.2523958\times 10^{7}}$

= $3.9620\times 10^{-7} m$

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Now, for $n_{1}$ = 2 and $n_{2}$ = 5

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{5^{2}} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.04 )$

= $1.0973731568508 \times 10^{7} \times (0.21 )$

= $0.230 \times 10^{7}$

$\lambda= \frac{1}{0.230 \times 10^{7}}$

= $4.3478 \times 10^{-7} m$

= $434.78\times 10^{-9} m$

= $434.78 nm$

Now, for $n_{1}$ = 2 and $n_{2}$ = 4

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{4^{2}} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.0625 )$

= $1.0973731568508 \times 10^{7} \times (0.1875 )$

= $0.20575 \times 10^{7}$

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= $4.8602 \times 10^{-7} m$

= $486.02 \times 10^{-9} m$

= $486.02 nm$

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= $1.0973731568508 \times 10^{7} \times (0.13 )$

= $0.1426585\times 10^{7}$

$\lambda= \frac{1}{0.1426585\times 10^{7}}$

= $7.0097 \times 10^{-7} m$

= $700.97 \times 10^{-9} m$

= $700.97 nm$

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