We have to calculate the number of carbon atoms present in 2-carat pure diamond.
The number of carbon atoms present in 2-carat pure diamond is: 0.19 X 10²³ number of carbon atom.
Diamond is one allotrope of carbon. Atomic mass of carbon is 12.
Mass of one mole carbon atom is 12 g. One mole carbon contains Avogadro's number i.e, 6.023 X 10²³ number of atoms.
0.40 g diamond contains 0.40/12 moles= 0.033 moles of carbon atom.
So, number of carbon atoms present in 0.40 g diamond (i.e, 0.033 mole diamond) is 0.033 X 6.023 X 10²³= 1.98 X 10²²=0.19 X 10²³ .
Therefore, 0.19 X 10²³ number of carbon atoms are in a 2-carat pure diamond that has a mass of 0.40 g
) adding phosphoric acid, said phosphoric acid reacting with said calcium carbonate to release gaseous carbon dioxide bubbles, and said water providing water of hydration to said plaster of Paris to form gypsum that sets around said carbon dioxide bubbles thereby forming said foamed plaster.
Inhibition of protein synthesis is the mode of action done by most antifungal drugs.
<h3>What is the mode of action of antifungal drugs?</h3>
Antifungals drugs inhibit the synthesis of ergosterol the main fungal sterol, polyenes which interact with fungal membrane sterols and 5-fluorocytosine inhibits macromolecular synthesis.
So we can conclude that inhibition of protein synthesis is the mode of action done by most antifungal drugs.
Learn more about drug here: brainly.com/question/26254731
Answer:
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