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notka56 [123]
3 years ago
15

Zinc metal and lead II nitrate yields zinc nitrate and lead metal

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

i odnt knwonwta whyour sayong

Explanation:

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Two solids of identical mass, A and B, are analyzed using identical calorimeters. Each calorimeter contains the same amount of w
DIA [1.3K]

Answer:

Specific heat of solid A is greater than specific heat of solid B.

Explanation:

In the calorimeter, as the temperature is increasing, the vibrational kinetic energy will increase and this means that additional amount of energy will be needed to increase the temperature by the same value. Therefore, we can conclude that specific heat increases as temperature increases.

Now, we are told that the final temperature of solid A's calorimeter is higher than that of B.

This means from our definition earlier, Solid A will have a higher specific heat that solid B.

5 0
3 years ago
Why potassium by sulphite or KHSO4 donot preserve meat
Debora [2.8K]

Answer:

Postassium bisulphate - KHSO4 - can be used as an food preservative to protect the food from micro-organisms.

4 0
3 years ago
The wavelength idea of the wave-mechanical model refers to what?
Virty [35]
<span> The wave idea derives from the electrons' behavior about the nucleus of an atom, and it follows Heisenberg's Uncertainty Principle and draws away from Bohr's planetary model of the atom.</span>
6 0
3 years ago
3. In a typical titration experiment a student titrates a 5.00 mL sample of formic acid (HCOOH), a monoprotic organic acid, with
ira [324]

Answer:

2.893 x 10⁻³ mol NaOH

[HCOOH] = 0.5786 mol/L

Explanation:

The balanced reaction equation is:

HCOOH + NaOH ⇒ NaHCOO + H₂O

At the endpoint in the titration, the amount of base added is just enough to react with all the formic acid present. So first we will calculate the moles of base added and use the molar ratio from the reaction equation to find the moles of formic acid that must have been present. Then we can find the concentration of formic acid.

The moles of base added is calculated as follows:

n = CV = (0.1088 mol/L)(26.59 mL) = 2.892992 mmol NaOH

Extra significant figures are kept to avoid round-off errors.

Now we relate the amount of NaOH to the amount of HCOOH through the molar ratio of 1:1.

(2.892992 mmol NaOH)(1 HCOOH/1 NaOH) = 2.892992 mmol HCOOH

The concentration of HCOOH to the correct number of significant figures is then calculated as follows:

C = n/V = (2.892992 mmol) / (5.00 mL) = 0.5786 mol/L

The question also asks to calculate the moles of base, so we convert millimoles to moles:

(2.892992 mmol NaOH)(1 mol/1000 mmol) = 2.893 x 10⁻³ mol NaOH

7 0
3 years ago
If the density of lead is 11.342 what would be the volume of a 200.0 g sample of metal
Valentin [98]
The answer would be 17.561cm^3
4 0
3 years ago
Read 2 more answers
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