Zinc metal and lead II nitrate yields zinc nitrate and lead metal
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Answer:
Explanation:
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In this case, according to this question, we will need to deal with this dilution problem, because it is asking for the volume of a 12.1-M stock solution of HCl. In such a way, we can use the following equation, under the assumption of no change in the number of moles in the solution:
Thus, we solve for the initial volume, V1, as shown below:
And plug in the initial concentration and final concentration and volume to obtain:
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