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Nastasia [14]
3 years ago
10

3. In a typical titration experiment a student titrates a 5.00 mL sample of formic acid (HCOOH), a monoprotic organic acid, with

26.59 mL of 0.1088 M NaOH. At this point the indicator turns pink. Calculate the # of moles of base added and the concentration of formic acid in the original sample.
Chemistry
1 answer:
ira [324]3 years ago
7 0

Answer:

2.893 x 10⁻³ mol NaOH

[HCOOH] = 0.5786 mol/L

Explanation:

The balanced reaction equation is:

HCOOH + NaOH ⇒ NaHCOO + H₂O

At the endpoint in the titration, the amount of base added is just enough to react with all the formic acid present. So first we will calculate the moles of base added and use the molar ratio from the reaction equation to find the moles of formic acid that must have been present. Then we can find the concentration of formic acid.

The moles of base added is calculated as follows:

n = CV = (0.1088 mol/L)(26.59 mL) = 2.892992 mmol NaOH

Extra significant figures are kept to avoid round-off errors.

Now we relate the amount of NaOH to the amount of HCOOH through the molar ratio of 1:1.

(2.892992 mmol NaOH)(1 HCOOH/1 NaOH) = 2.892992 mmol HCOOH

The concentration of HCOOH to the correct number of significant figures is then calculated as follows:

C = n/V = (2.892992 mmol) / (5.00 mL) = 0.5786 mol/L

The question also asks to calculate the moles of base, so we convert millimoles to moles:

(2.892992 mmol NaOH)(1 mol/1000 mmol) = 2.893 x 10⁻³ mol NaOH

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Explanation:

3 0
2 years ago
Cacl2+na3po4 ca3po42 + nacl
Alex787 [66]
<h3>Answer:</h3>

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

<h3>Explanation:</h3>

We are given the Equation;

CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl

Assuming the question requires us to balance the equation;

  • A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
  • Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
  • According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
  • Balancing chemical equations involves putting appropriate coefficients on the reactants and products.

In this case;

  • To balance the equation we are going to put the coefficients 3, 2, 1, and 6.
  • Therefore; the balanced equation will be;

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

5 0
3 years ago
In which system does a spontaneous redox reaction produce electrical energy?
Vladimir [108]
Had to look for the options and here is my answer.
When we say that a redox reaction is spontaneous, this would mean that there is a formation of positive voltage <span>across the electrodes of a voltaic cell. Therefore, the system that this kind of reaction produces electrical energy is in a GALVANIC CELL. Hope this helps.</span>
3 0
2 years ago
Write the balanced equation for the neutralization reaction between HCl and Ba(OH)2 in an aqueous solution. Phases are optional.
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Explanation:

2HCl + Ba(OH)2 ------> BaCl2 + 2H2O

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The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th
OLga [1]

Answer:

ΔH = -162.5 kJ.

Explanation:

Hello.

In this case, we first rearrange the reactions:

ClO(g) + O₃(g) ⇒ Cl(g) + 2O₂(g);  ΔH =-122.8 kJ

2O₃(g) ⇒ 3O₂(g);  ΔH=-285.3 kJ

O₃(g) + Cl(g) ⇒ ClO(g) + O₂(g);  ΔH= ?

Thus, we are going to use the Hess law, as an strategy to rearrange the known chemical reactions and thereby compute the enthalpy of reaction of the unknown one.

1. The first reaction must be inverted in order to obtain chlorine as a reactant in the third one, therefore, the enthalpy of reaction becomes positive:

Cl(g) + 2O₂(g) ⇒ ClO(g) + O₃(g);   ΔH = 122.8 kJ

2. Second reaction remains the same:

2O₃(g) ⇒ 3O₂(g);  ΔH=-285.3 kJ

Then, we add them to obtain:

Cl(g) + 2O₂(g) + 2O₃(g) ⇒ ClO(g) + O₃(g) + 3O₂(g)

Whereas we can subtract both oxygen and ozone to obtain the third one:

O₃(g) + Cl(g) ⇒ ClO(g) + O₂(g)

Therefore, the enthalpy of reaction turns out:

ΔH = 122.8 kJ + (-285.3 kJ )

ΔH = -162.5 kJ.

Best regards.

4 0
3 years ago
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