Please help me.....

A recipe for 1 lb of trail mix calls for 2.5 oz of chocolate pieces. How many ounces of chocolate pieces are needed to make 5 lb

Murljashka [212]

5 lb of trail mix* (2.5 oz of chocolate pieces/ 1 lb of trail mix)= 12.5 oz of chocolate pieces.
(Note that the unit cancels out so you get the answer)

The final answer is 12.5 oz of chocolate pieces~

5 0

3 years ago

Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i

Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let X = r = a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = p = 0.35.

The sample selected is of size n = 12.

The random variable X follows a Binomial distribution with parameters n = 12 and p = 0.35.

The probability function of a binomial random variable is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x}$

(a)

For X = 0 the probability is:

$P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006$

For X = 1 the probability is:

$P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037$

For X = 2 the probability is:

$P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109$

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

$E(X)=np$

The expected number of vehicles out of 12 that will tailgate is:

$E(X)=np=12\times0.35=4.2$

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

$SD(X)=np(1-p)$

The standard deviation of vehicles out of 12 that will tailgate is:

$SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\$

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0

3 years ago

In the barn, there are horses and chickens. There are 11 heads and 32 legs altogether. How many chickens are there?

Masteriza [31]

Answer:

6 Chickens

Step-by-step explanation:

Let H represent the number of horses and C represent the number of chickens. Since there are 32 legs altogether this means that on equation to use would be given by:

2C + 4 H = 32 (Eq. 1)

Another equation can be made from the fact that there are 11 heads or 11 animals altogether which can be written as:

C + H = 11 (Eq. 2)

From Eq. 2, solve for the number of chickens:

C + H = 11

C = 11 - H (Eq. 3)

Substituting Eq. 3 in Eq. 1, the number of horses can be determined:

2 C + 4 H = 32

2 ( 11 − H ) + 4 H = 32

22 − 2 H + 4 H = 32

2H = 32 − 22

2 H = 10

H = 5 Eq.4

Putting Eq.4 in Eq.1

2C + 4*5 = 32

2C = 32 - 20

2C = 12

C = 12/2

C = 6

8 0

3 years ago

Can you organize collections of numbers into mathematical sets?

Bezzdna [24]

Yes by 10's and hundreds and ones place and even and odd. And pine and composite

6 0

3 years ago

Coefficient What is the coefficient in the equations 8 = 2y + 3

miskamm [114]

2 is the coefficient. Y is 2.5

8 0

3 years ago