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2 years ago

What is the coefficient of y in the expression 3 ⋅ 4 + 5y?

Mathematics

2 answers:

ZanzabumX [31]2 years ago

7 0

<h3>Answer: 5</h3>

The coefficient is the term just to the left of the variable. So for the term 5y, the number to the left of y is 5.

extra info: 5y is the same as 5*y or "5 times y", where y is a placeholder for some unknown number.

mihalych1998 [28]2 years ago

4 0

Answer:

Step-by-step explanation:

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almond37 [142]

The ratio from 80 to 5 would be 16. so divide 144 by 16 and you get 9. Answer:9

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2 years ago

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Is the following relation a function? Give the domain and range

Angelina_Jolie [31]

That relaton i a function

3 0

2 years ago

How do I solve for x?

mel-nik [20]

Answer:

x = 4.8

Step-by-step explanation:

Since quadrilateral JKLM and PQRS are similar toe ach other, therefore the ratio of their corresponding sides are equal.

Thus:

QP/KJ = PS/JM

Substitute

8/5 = x/3

Cross multiply

5*x = 3*8

5x = 24

x = 24/5

x = 4.8

3 0

2 years ago

Se vendieron 50 camisetas a 10€ a cada una.¿ que beneficio se obtuvo si las camisetas se compraron a 7€ cada uno?

ipn [44]

the question in English

50 t-shirts were sold at 10€ each. What benefit was obtained if the t-shirts were bought at 7€ each?

Let

x---------> the benefit in euros

we know that

$x=50*10-50*7$

$x=50*(10-7)$

$x=50*3$

$x=150\ euros$

therefore

<u>the answer is</u>

The benefit is equal to $150\ euros$

6 0

3 years ago

55. If 3x = 4y, the value of (x + y)^2 : (x - y)^2 is:<br>

ladessa [460]

Answer:

$\large\boxed{(x+y)^2:(x-y)^2=49}$

Step-by-step explanation:

$3x=4y\qquad\text{subtract}\ 3y\ \text{from both sides}\\\\3x-3y=y\qquad\text{distributive}\\\\3(x-y)=y\qquad\text{divide both sides by 3}\\\\x-y=\dfrac{y}{3}\qquad(*)\\------------------\\3x=4y\qquad\text{add}\ 3y\ \text{to both sides}\\\\3x+3y=7y\qquad\text{distributive}\\\\3(x+y)=7y\qquad\text{divide both sides by 3}\\\\x+y=\dfrac{7y}{3}\qquad(**)\\------------------$

$(x+y)^2:(x-y)^2=\dfrac{(x+y)^2}{(x-y)^2}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\=\left(\dfrac{x+y}{x-y}\right)^2\qquad\text{substitute}\ (*)\ \text{and}\ (**)\\\\=\left(\dfrac{\frac{7y}{3}}{\frac{y}{3}}\right)^2=\left(\dfrac{7y}{3}\cdot\dfrac{3}{y}\right)^2\qquad\text{cancel}\ 3\ \text{and}\ y\\\\=(7)^2=49$

5 0

2 years ago