The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.
A(t) = A(o) (1/2)^(t/d)
where t is the certain period of time. Substituting the known values,
A(t) = (20 mg)(1/2)^(85.80/14.30)
Solving,
A(t) = 0.3125 mg
Hence, the answer is 0.3125 mg.
Answer:
1. KCLO3------>KCL + 3/2O2(g)
2. 122.5g/mol
3. 0.2mol
4. 18.5g
The implications are for this reader in this line is that the atom is belonging to some kind of system and it is good belonging to that system.
Hope this helps. :)
- Shelly O
Answer:
The formula for the precipitate is PbI₂
Explanation:
The chemical reaction is:
Pb(NO₃)₂ (aq) + 2KI (aq) → 2KNO₃ (aq) + PbI₂ (s)↓
All the iodides, with these cations (Ag⁺, Pb²⁺, Cu⁺, Hg²⁺, Bi⁺³ and Sn⁺⁴) produce insolubles solid.
