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cestrela7 [59]
3 years ago
12

Factor 3x^3+6x^2+x+2 by grouping

Mathematics
2 answers:
bezimeni [28]3 years ago
7 0
The answer for this question when grouping:

(x+2)(3x^2+1)
UkoKoshka [18]3 years ago
7 0
3x^3 + 6x^2 + x +2

Let's divide the question into the left and right side:
The left side:
3x^3 + 6x^2
Take out the greatest common factor (3x^2)
3x^2(x+2)

Now the right side:
x+2
Take out greatest common factor (1)
1(x+2)


Notice how each side has a parenthesis of (x + 2); this is good. We combine the matching elements into one, and take the greatest common factors we pulled and make them into a group. As shown:

(3x^2 +1) is the two greatest common factors we pulled.

(x+2) is the common parenthesis.
Now combine them for your answer:

(3x^2+1)(x+2) is your factored answer.

I hope this Helps!
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Answer:

Y= -8

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Step-by-step explanation:

apply -(-a)=a rule

-23+4*8/3

-23+4*8=9

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7 0
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ikadub [295]

Step-by-step explanation:

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Question 1 (1 point)
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Answer:

See below

Step-by-step explanation:

1) x=2-1

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2 years ago
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

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Hence, the rocket hits the ground after 18.75 seconds.

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