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scZoUnD [109]
3 years ago
12

Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe

ses 6 minus 6 i close parenthe . (6 points)
1. quantity of negative 3 minus 6 i over 5
2. quantity of 39 minus 6 i over negative 9
3. quantity of negative 39 minus 6 i over 17
4. quantity of 3 minus 6 i over 3
Mathematics
1 answer:
Deffense [45]3 years ago
8 0
A calculator shows
\dfrac{\sqrt{-9}}{(4-7i)-(6-6i)}=\dfrac{3i}{-2-i}=-3\cdot\dfrac{i(2-i)}{2^2+1^2}\\\\=\dfrac{-3-6i}{5}
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Can somebody pls show me how to solve this?
fomenos

Answer:

C. 52.5

Step-by-step explanation:

The total from W(-20) to Z(120) is 140.

You can add up all of the numbers in the ratio, 2:3:3, to get 8

Divide 140 by 8 to get 17.5

Multiply 17.5 times the number in the ratio for each segment, so the new ratio would be 35 : 52.5 : 52.5

Since you are trying to find segment XY, which was the 2nd number in the ratio, you would get your answer as 52.5

8 0
3 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
Claire is going to invest $2,600 and leave it in an account for 18 years. Assuming the interest is compounded continuously, what
Bogdan [553]

Answer:

Rate of interest r = 2.83 % (Approx.)

Step-by-step explanation:

Given:

Amount invested p = $2,600

Amount get A = $4,300

Number of year n = 18

Find:

Rate of interest r

Computation:

A = p(1+r)ⁿ

4,300 = 2,600(1+r)¹⁸

(1+r)¹⁸ = 1.653846

Rate of interest r = 2.83 % (Approx.)

8 0
3 years ago
Read 2 more answers
Solve the system of equations.<br> ​<br><br> 2x−9y=14<br> x=−6y+7<br> ​
ipn [44]

Step-by-step explanation:

put \: x \: into \: equation \: 1

2( - 6y + 7) - 9y = 14

- 12y + 14 - 9y = 14

- 21y + 14 = 14

- 21y = 14 - 14

- 21y = 0

\frac{ - 21y}{12}  =  \frac{0}{21}

y = 0

put \: y = 0 \: into \: equation \: 2

x = 6y + 7

x = 6(0) + 7

x = 0 + 7

x = 7

3 0
2 years ago
Read 2 more answers
The time between failures of a machine has an exponential distribution with parameter l. Suppose that the prior distribution for
ololo11 [35]
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