Answer:
The induced current and the power dissipated through the resistor are 0.5 mA and
.
Explanation:
Given that,
Distance = 1.0 m
Resistance = 3.0 Ω
Speed = 35 m/s
Angle = 53°
Magnetic field 
(a). We need to calculate the induced emf
Using formula of emf

Where, B = magnetic field
l = length
v = velocity
Put the value into the formula


We need to calculate the induced current


Put the value into the formula


(b). We need to calculate the power dissipated through the resistor
Using formula of power

Put the value into the formula


Hence, The induced current and the power dissipated through the resistor are 0.5 mA and
.
Answer:

Explanation:
t = Time taken = 
i = Current = 3 A
q(0) = Initial charge =
Charge is given by

The magnitude of the net electric charge of the capacitor is 
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Answer
given,
Two solenoids A and B
Number of turn
Na = 430 turns Nb = 610 turns
Current = 2.80 A
Average flux through A = 300 μWb
Average of flux through B = 90.0 μ
Wb
a) 


b) inductance of A



c) magnitude of the emf




Inductive reactance (Z) = ω L = 2Πf L = (2Π) (12,000) (L)
I = V / Z
4 A = 16v / (24,000Π L)
Multiply each side by (24,000 Π L):
96,000 Π L = 16v
Divide each side by (96,000 Π) :
L = 16 / 96,000Π = 5.305 x 10⁻⁵ Henry
L = 53.05 microHenry