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nevsk [136]
3 years ago
11

Which type of electronic exchange connects buyers with sellers within a specific industry?

Physics
1 answer:
Sonja [21]3 years ago
5 0
I think the correct answer would be horizontal exchanges or market. It is a type of market wherein a service or a product would meet a need of a very wide range of consumers from different sectors. Hope this answers the question. Have a nice day.
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Can someone help with just question 1 :)
Elanso [62]
Can you show the full question?
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3 years ago
When a red giant completes helium fusion and collapses, it becomes a ______.
Firdavs [7]
<span>When a red giang complete helium fusion and collapses, it becomes a white dwarf. The correct option is C. White dwarf are very dense stars that are usually the size of a planet. It is a stellar core reminant which mainly made up of electron degenerated matters; its mass is comparable to that of the sun while its volume is comparable to that of the earth. </span>
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3 years ago
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The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi
Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which   describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}

Where,

B= Magnetic Field

l = length

\mu_0 = Vacuum permeability

\epsilon_0 = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}

Recall that the speed of light is equivalent to

c^2 = \frac{1}{\mu_0 \epsilon_0}

Then replacing,

B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}

B = \frac{r}{2C^2} \frac{dE}{dt}

Our values are given as

dE = 2150N/C

dt = 5s

C = 3*10^8m/s

D = 0.440m \rightarrow r = 0.220m

Replacing we have,

B = \frac{r}{2C^2} \frac{dE}{dt}

B = \frac{0.220}{2(3*10^8)^2} \frac{2150}{5}

B =5.25*10^{-16}T

Therefore the magnetic field around this circular area is B =5.25*10^{-16}T

3 0
3 years ago
A tennis player strikes a tennis ball from underneath with her racket. The ball is sent straight up with an initial velocity of
Stels [109]
So the acceleration of gravity is 9.8 m/s so that’s how quickly it will accelerate downwards. You can use a kinematic equation to determine your answer. We know that initial velocity was 19 m/s, final velocity must be 0 m/s because it’s at the very top, and the acceleration is -9.8 m/s. You can then use this equation:

Vf^2=Vo^2+2ax

Plugging in values:

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6 0
3 years ago
Why is the big bang called a theory?<br>​
viva [34]
There is no scientific way to prove that it happened it’s like a hypothesis without being able to test the hypothesis
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