At the start of the 0.266 s, the object's speed was 8.26 m/s.
The question can only be talking about speed, not velocity.
Answer:
ΔF=125.22 %
Explanation:
We know that drag force on the car given as

=Drag coefficient
A=Projected area
v=Velocity
ρ=Density
All other quantity are constant so we can say that drag force and velocity can be given as

Now by putting the values



Percentage Change in the drag force



ΔF=125.22 %
Therefore force will increase by 125.22 %.
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Answer:
Height, h = 16.67 m
Explanation:
We have,
Mass of a squirrel is 0.765 kg.
He jumps off the tree and hits the ground with 125 joules of energy.
It is required to find the height up on the tree the squirrel was when it jumped.
The energy possessed by the squirrel is called its gravitational potential energy. It can be given by :

h is height up on the tree the squirrel was when it jumped

So, the squirrel will go to a height of 16.67 m.
The first blank is character
The last one is eye colour.