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4 years ago

How do two sublevels of the same principal energy level differ from each other

Physics

1 answer:

Colt1911 [192]4 years ago

7 0

Each energy sublevel corresponds to an orbital of a different shape.

Explanation:

Two sublevels of the same principal energy level differs from each other if the sublevels corrresponds to an orbital of a different shape.

The principal quantum number of an atom represents the main energy level in which the orbital is located or the distance of an orbital from the nucleus. It takes values of n = 1,2,3,4 et.c
The secondary quantum number gives the shape of the orbitals in subshells accommodating electrons.
The number of possible shapes is limited by the principal quantum numbers.

Take for example, Carbon:

1s² 2s² 2p²

The second energy level is 2 but with two different sublevels of s and p. They have different shapes. S is spherical and P is dumb-bell shaped .

Learn more:

Quantum number brainly.com/question/9288609

#learnwithBrainly

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Electrical current is defined as

Dmitry_Shevchenko [17]

Explanation:

The flow of electrical charge per unit time

8 0

3 years ago

An 800 N man climbs 5 m up a ladder. How much gravitational potential energy does he gain?

Artemon [7]

Answer:

4000J

Explanation:

Given parameters:

Weight of the man = 800N

Height of ladder = 5m

Unknown:

Gravitational potential energy gained = ?

Solution:

The gravitational potential energy is due to the position of a body.

Gravitational potential energy = weight x height

Now insert the parameters;

Gravitational potential energy = 800 x 5 = 4000J

5 0

4 years ago

Two charges of magnitude +q are separated by a distance d. Assuming there are no changes to anything else, but the charges are s

erma4kov [3.2K]

Answer:

The Coulomb force between them will decrease by a factor of 1/9

Explanation:

The Coulomb's force acting between two particles of equal charge, q, separated by a distance, d, is given as:

$F = \frac{kq^2}{d^2}$

where k = Coulomb's constant

If they are separated by 3 times their current distance, the new distance becomes 3d. Hence, the Coulomb force acting between them becomes:

$F_n = \frac{kq^2}{(3d)^2}\\ \\\\F_n = \frac{kq^2}{9d^2} \\\\\\F_n = \frac{1}{9} F$

Hence, the Coulomb force decreases by a factor of 1/9.

4 0

3 years ago

Read 2 more answers

I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block

borishaifa [10]

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

$T = 2\pi \sqrt{\frac{m}{k} }$

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

$T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\$

Now, determine the amplitude of oscillation, A;

$E = \frac{1}{2} kA^2$

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

$E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A = \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm$

Therefore, the amplitude of the oscillation is 2.82 cm

8 0

3 years ago

To determine the amplitude of a wave, you would need to know the . A) distance from the crest to the trough. B) maximum displace

Alexxx [7]

To determine the amplitude of a wave, you would need to know the : B. Maximum displacement of the wave from the equilibrium position

You can find out the displacement by counting the waves that is
written on the Graph

Hope this helps

4 0

3 years ago

Read 2 more answers