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vesna_86 [32]
3 years ago
5

Isthere an outward force in circular motion

Physics
2 answers:
Sladkaya [172]3 years ago
8 0

no there isn't. the cause of circular motion is centripetal force.

centripetal force : a force that causes an object to move in a circle

 

asambeis [7]3 years ago
7 0

No, there is no such thing as an outward force that goes in a circular motion.

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What is a gravitational wave and why was it so hard to detect?
Alika [10]

Answer:

gravitational waves are ripples in spece-time caused primarily when objects are accelerated and the energy for the acceleration is transpoted as gravitational radiation.

they are difficult to detect because they require very sensitive technology or you will have to wait unitl black holes collide.

5 0
3 years ago
PLS HELP. WILL GIVE BRAINLIEST. PLS THIS IS WORTH 35 POINTS ON MY TEST
Nata [24]

Answer:

18m/s^2

Explanation:

Vf = Vi + at

t = distance/ average velocity

(120 + 0)/2 = 60 (average velocity)

400m/60m/s = 20/3 s

insert into first equation:

120 = 0 + a(20/3)

360 = 20a

18 = a

HOPE THIS HELPS!!!

5 0
2 years ago
Read 2 more answers
Why is an iceberg more dense than a ship?
Serhud [2]

Answer:

icebergs float on water because ice is less dense than water. The same is true for a boat: a boat floats on water because, overall, it is less dense than the water.

Explanation:

7 0
2 years ago
A car starts from rest with an acceleration of 8 m/s/s for a time of 4 s. What was the car's final velocity?
Aleks [24]
32m/s
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6 0
2 years ago
A missle is fired horizontally with an initial velocity of 45 m/s from the top of a building 75 m high.
NARA [144]

The horizontal range of the missile is b) 176 m

Explanation:

The motion of the missile is a projectile motion, so it consists of two independent motions:  

- A uniform motion with constant velocity along the horizontal direction  

- A uniformly accelerated motion with constant acceleration (equal to the acceleration of gravity) in the vertical-downward direction  

To find the time of flight of the missile, we study the vertical motion. We can use the following suvat equation:

s=u_y t+\frac{1}{2}at^2

where:

s = 75 m is the vertical displacement of the missile (the height of the building)

u_y=0 is the initial vertical velocity  (the missile is thrown horizontally)

t is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find the time of flight:

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(75)}{9.8}}=3.91 s

This means that the missile takes 3.91 s to reach the ground.

Now we study the horizontal motion: the missile moves with a constant horizontal velocity of

v_x = 45 m/s

Therefore, the distance covered in a time t is

d=v_x t

and by substituting t = 3.91 s, we find the horizontal range of the missile:

d=(45)(3.91)=176 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

4 0
4 years ago
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