Well velocity is a vector quanity and we can brake vectors in to verticle and horizantal componontes threw these two formulas Vcostheta=Vx and Vsintheta=Vy
Answer:
424.26 m/s
Explanation:
Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q
The relative speed will be calculated by using pythagorean theorem
Relative speed = sqrt(300^2 + 300^2)
Relative speed = sqrt( 180000 )
Relative speed = 424.26 m/s
Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s
(a) is a decomposition reaction
Answer:
Explanation:
The time the stone takes to fall can be calculated considering only the vertical component with the formula:
Taking the inital height as 0m and downward direction positive, since it departs from (vertical) rest we have:
Which gives us a time:
Horizontally, on that time the stone travelled a distance x=10m, which means its horizontal speed was:
Since <u>this speed is the tangential velocity</u> while whirling, the centripetal acceleration of the stone was:
