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3 years ago

Isthere an outward force in circular motion

Physics

2 answers:

Sladkaya [172]3 years ago

8 0

no there isn't. the cause of circular motion is centripetal force.

centripetal force : a force that causes an object to move in a circle

asambeis [7]3 years ago

7 0

No, there is no such thing as an outward force that goes in a circular motion.

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Suppose a car is traveling in the negative x-direction and comes to a stop. What is the sign of that car’s acceleration? How do

Oduvanchick [21]

We have equation of motion v = u + at

Where v = final velocity, u = initial velocity, a = acceleration, and t = time

In this case car is travelling in -x direction

Velocity of car = displacement / time

Since displacement value is increasing in negative x axis it's initial velocity is negative

And it's final velocity is zero since it comes to rest, and time is also positive

So, v= u+ at => 0 = -u + at

So, a = u/t

Which is positive and along positive X - direction

7 0

4 years ago

The volume of a ball was measured at 500.0 cm3, and its mass was measured to be 404.2 g.

KonstantinChe [14]

Answer:

0.8084g/cm³

Explanation:

For calculating density, mass is divided by volume.

Its units is commonly in grams per cubic centimeters.

Therefore,

density= mass/volume

= 404.2/500

=0.8084g/cm³

4 0

3 years ago

Read 2 more answers

What is the speed of light in (a) crown glass n= 1.52, (b) Lucite n = 1.51, and (c) ethyl alcohol n = 1.36?

mote1985 [20]

Answer:

$(a)\\1.97\times 10^8 m/s\\(b)\\1.99\times 10^8 m/s \\(c)\\2.21 \times 10^8 m/s$

Explanation:

According to the definition of refractive index, the refractive index of the material is defined as the ratio of speed of light in vacuum to the speed of light in medium.

(a) refractive index, n = 1.52

$n=\frac {c}{v}\\\\1.52 = \frac{3\times 10^8}{v}\\\\v = 1.97\times 10^8 m/s$

(b) refractive index, n = 1.51

$n=\frac {c}{v}\\\\1.51 = \frac{3\times 10^8}{v}\\\\v = 1.99\times 10^8 m/s$

$n=\frac {c}{v}\\\\1.36 = \frac{3\times 10^8}{v}\\\\v = 2.21\times 10^8 m/s$

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3 years ago

You arrive at an intersection with traffic lights that are not working because of a power outage. What do you do?

d1i1m1o1n [39]

You act as it is a four way stop

8 0

3 years ago

Read 2 more answers

A small asteroid with a mass of 1500 kg moves near the earth. At a particular instant the asteroid’s velocity is ⟨3.5 × 104, −1.

zalisa [80]

Answer:

$P_{f}$ =(5.7 x $10^{7$ i - 2.24 x $10^{7$ j) kgm/s

Explanation:

Due to earths gravity, force on asteroid is given by:

$F= \frac{Gm_{1}m_{2} }{r^{2} }$ r^

Plugging in the values, we have

F= [(6.67x $10^{-11}$ )(1500)(5.97 x $10^{24}$ )(8x $10^{6}$ i + 9x $10^{6$ j)] / ((8x $10^{6}$ )² + (9x $10^{6$ )² $)^{1.5}$

F= 2736 i^ + 3078 j^

In order find the final momentum of the Asteroid, apply impulse momentum theorem

$P_{f}$ = $P_{i$ + FΔt

$P_{f}$ = 1500(3.5 x $10^{4$ i - 1.8x $10^{4$ j) + (2736i + 3078j)(1.5x $10^{3$ )

$P_{f}$ =(5.7 x $10^{7$ i- 2.24 x $10^{7$ j)kgm/s

4 0

4 years ago