when Kc = [the concentration of products]^(no.of its mol in the balanced equation) / [the concentration of the reactants]^(no.of mol in the balanced equation)
∴ The equilibrium constant expression for this reaction is:
Kc= [H+]^2 * [So4-2] / [H2SO4]
Answer by YourHope:
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Answers:
A catalyst is a substance that changes the rate of the reaction, and is not consumed in the reaction!
A solution is a uniform mixture of molecules or ions of one substance in another!
A solute is the substance dissolved in a solution!
A solution is the substance that does the dissolving in a solution!
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Answer:
The hydrogen ion concentrations associated with these pH value 7.35 is 
The hydrogen ion concentrations associated with these pH value 7.45 is 
.
Explanation:
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
1) pH = 7.35
Putting values in above equation, we get:
![7.35=-\log[H^+]](https://tex.z-dn.net/?f=7.35%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=4.467\times 10^{-8} M\approx 4.5\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D4.467%5Ctimes%2010%5E%7B-8%7D%20M%5Capprox%204.5%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentrations associated with these pH value 7.35 is
2) pH = 7.45
Putting values in above equation, we get:
![7.45=-\log[H^+]](https://tex.z-dn.net/?f=7.45%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=3.548\times 10^{-8}M \approx 3.6\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D3.548%5Ctimes%2010%5E%7B-8%7DM%20%5Capprox%203.6%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentrations associated with these pH value 7.45 is .
True. An element's properties are based on their atomic numbers, atomic masses and electron configurations.
Hope it helped!
The substance which is a combination of different atoms is a compound.
