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Dafna11 [192]
3 years ago
7

I need help with this. 2 to the 6 power, +2 to the 3 power, raised to the 3 power. Please tell me the steps you took to get the

answer. and happy. Christmas Eve

Mathematics
2 answers:
Vlada [557]3 years ago
8 0

Answer: 576

Step-by-step explanation:

(I just know the powers of smaller numbers by memory so...)

2^6(2x2x2x2x2x2) = 64

You can simplify the second part( 2^3^3) by just multiplying the powers, 3x3 = 9 and 2^9 = 512

Final answer = 512 + 64 = 576

mamaluj [8]3 years ago
3 0

\\ \sf\Rrightarrow 2^6+(2^3)^3

\\ \sf\Rrightarrow 2^6+2^9

\\ \sf\Rrightarrow 64+512

\\ \sf\Rrightarrow 576

Option A is correct

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If q/18 = 5 what does q = to
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Answer:

Q= 90

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Challenge Yossi used to have a square garage with 246 ft of floor space. recently built an addition to it. The garage is still a
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Considering the perimeter of a square, it is found that:

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<h3>What is the perimeter of a square?</h3>

The perimeter of a square of side length s is given by four times the length, that is:

P = 4s.

Before the change, the perimeter was of 246 ft, hence:

4s = 246

s = 246/4

s = 61.5.

The length of one side of the garage​ originally was of 61.5 ft.

After that, the perimeter increased by 50%, hence:

P = 246 x 1.5 = 369.

4s = 369

s = 369/4

s = 92.25.

The length of one side of the garage​ now is of 92.25 ft.

The percent increase is the increase divided by the initial value, hence:

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The percent increase in the length of one​ side was of 50%.

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1 year ago
Kenji is decorating papers with a total of 15 heart stickers and 12 star stickers for the child he is babysitting. If he wants t
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Answer: The greatest number of pages Kenji can decorate = 3

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If all the papers identical, with the same combination of heart and star stickers and no stickers left over.

Then the greatest number of pages Kenji can decorate = GCD(15,12)  [GCD=greatest common divisor]

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GCD(15,12) =3

Hence, the greatest number of pages Kenji can decorate = 3

7 0
3 years ago
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