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3 years ago

Write 5,674,890 in word form

Mathematics

1 answer:

wolverine [178]3 years ago

5 0

It is; Five million Six hundred seventy four thousand eight hundred ninety. As simple as that.

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If the domain of the square root function f(x) is x

soldier1979 [14.2K]

<span>This question, in my opinion, is not well stated. If f(x) = √x, as the question statement seems to say, then the domain is not x<7. Rather, the domain is x≥0. If f(x) is not the square root function, but say f(x) = √(7-x) then the domain is x≤7, and for this function then the appropriate answer is d), since the x-term inside the radical has a negative coefficient.</span>

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2 years ago

Karen has a summer job as a swim instructor. she gets paid $4 per hour for the first 20 hours and $6 per hour for each hour in t

Misha Larkins [42]

She would need to work 24 hours because the first 20hrs x $4 is $80 $104-$80 = 24
24\6= 4 20 plus 4 is 24

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2 years ago

6. (5 points) What is 3loga + logb − logc written as a single logarithm?

Jobisdone [24]

Answer: $log(\frac{a^3b}{c})$

Step-by-step explanation:

You need to use the following Properties of Logarithms:

$1)m*log(a)=log(a)^m\\\\2)log(a)+log(b)=log(ab)\\\\3)log(a)-log(b)=log(\frac{a}{b})$

Given the following expression:

$3log(a) + log(b) - log(c)$

You can follow these steps in order to write it as a single logarightm:

- Apply the first property shown above:

$=log(a)^3 + log(b) - log(c)$

- Apply the second property:

$=log(a^3b)- log(c)$

- Finally, apply the third property:

$=log(\frac{a^3b}{c})$

4 0

3 years ago

What is the scale factor of the dilation shown?<br><br> (Help please) geometry

elixir [45]

The answer is 2/3 I hope it helped

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2 years ago

Need help with a simple problem 2^x=3^x+1

KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
Those ranges don't have a common part, therefore, again, no solution.

So, the equation $2^x=3^x+1$ doesn't have a solution.

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3 years ago