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Vilka [71]
3 years ago
13

Triangle A C D is shown. Point B is near the center of the triangle. Angle A C D is bisected by line segment C B. Lines are draw

n from point B to points A and D to form 3 triangles within the larger triangle. Angle C B D is 125 degrees. The length of line segment A C is 52 centimeters and the length of line segment B D is 29 centimeters. If Line segment C B. bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three options. m∠ABC = 125° and AB ≅ DB ΔACD is isosceles with base AD ΔABD is isosceles with base AD CD = 52 cm AB = 29 cm
Mathematics
2 answers:
Vladimir [108]3 years ago
5 0

Answer:

A,B,D on edu :)

Step-by-step explanation:

astraxan [27]3 years ago
3 0

Answer:

m∠ABC = 125° and AB ≅ DB, ΔACD is isosceles with base AD, CD = 52 cm

Step-by-step explanation:

i just took the quiz

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I REALLY NEED HELP PLEASE 30 POINTS AND BRIANLIEST
Mademuasel [1]

Answer:

C is the closest one but it should be -472 instead -475

Step-by-step explanation:

just insert X in the formulas and compare to P

7 0
3 years ago
10 points
ollegr [7]

Answer:

FC=25.9

Step-by-step explanation:

<u>Congruent Triangles</u>

The figure shows two triangles FCD and FED. One of their sides is the radius of the circle, they both form a 90° angle with the line CD and ED and they share the same segment FD.

Thus, both triangles are congruent and we have the length of a side (12 units), one common side (the hypotenuse) and one unknown leg that must be equal. Therefore

13x-16=4x+11

Solving

9x=27

x=3

The required side FD is the hypotenuse of any of the triangles. The unknown leg can be calculated by

13x-16=23

Or

4x+11=23

Thus

FD^2=12^2+23^2=673

Solving

FD=\sqrt{673}

\boxed{FC=25.9}

5 0
3 years ago
What is the area of the given figure?
kirza4 [7]

\huge\boxed{192\ \text{in}^2}

There are three parts to this figure: a rectangle and two triangles that are congruent.

We'll add together the area for each to get the total area.

We'll start by finding the area of the rectangle. We don't know its length, so we need to find the bases of the triangles and add them together.

We know that a^2+b^2=c^2. Substitute and solve for a:

\begin{aligned}a^2+6^2&=10^2\\a^2+36&=100\\a^2+36-36&=100-36\\a^2&=64\\\sqrt{a^2}&=\sqrt{64}\\a&=8\end{aligned}

Now, double this to get the total length of the rectangle, which is 16 inches.

The area of the rectangle is equal to its length times its height:

16\cdot9=\underline{144}

Now, we'll find the area of one of the triangles and double it since they're congruent.

The area of a triangle is one-half of its base times its height, which we then double.

2\left(\frac{1}{2}\cdot b\cdot h\right)

The 2 and the \frac{1}{2} cancel each other out.

b\cdot h

Substitute and solve:

8\cdot6=\underline{48}

Finally, add the rectangle's area to the two triangles' area.

144+48=\boxed{192}

6 0
2 years ago
A football team earns 6 points for a touchdown and 3 points for a field goal. In one game, a team scored a touchdown and some fi
Alja [10]

Answer:

6+3(f)=18

6+3f=18

3f=12

f=4

Step-by-step explanation:

3 0
2 years ago
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