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Vilka [71]
3 years ago
13

Triangle A C D is shown. Point B is near the center of the triangle. Angle A C D is bisected by line segment C B. Lines are draw

n from point B to points A and D to form 3 triangles within the larger triangle. Angle C B D is 125 degrees. The length of line segment A C is 52 centimeters and the length of line segment B D is 29 centimeters. If Line segment C B. bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three options. m∠ABC = 125° and AB ≅ DB ΔACD is isosceles with base AD ΔABD is isosceles with base AD CD = 52 cm AB = 29 cm
Mathematics
2 answers:
Vladimir [108]3 years ago
5 0

Answer:

A,B,D on edu :)

Step-by-step explanation:

astraxan [27]3 years ago
3 0

Answer:

m∠ABC = 125° and AB ≅ DB, ΔACD is isosceles with base AD, CD = 52 cm

Step-by-step explanation:

i just took the quiz

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I need help) (only the answer) *links and wrong answers will be reorted*
scZoUnD [109]

Answer:

Volume of cuboid = 300 in³

Surface area of cuboid = 280 in²

Step-by-step explanation:

Given:

Length = 10 in

Width = 5 in

Height = 6 in

Find:

Volume of cuboid

Surface area of cuboid

Computation:

Volume of cuboid = [L][B][H]

Volume of cuboid = [10][5][6]

Volume of cuboid = 300 in³

Surface area of cuboid = 2[lb][bh][hl]

Surface area of cuboid = 2[(10)(5) + (5)(6) + (6)(10)]

Surface area of cuboid = 2[50 + 30 + 60]

Surface area of cuboid = 2[140]

Surface area of cuboid = 280 in²

4 0
2 years ago
The numerator of a given fraction is 4 less than the denominator. if 3 is subtracted from the numerator and 5 is added to the de
Sergeu [11.5K]

Answer:

Step-by-step explanation:Given that the numerator of a given fraction is 4 less than its denominator.

Also given that 3 is subtracted from the numerator and 5 is added to the denominator, the fraction becomes one by fourth .

Let the fraction be  

Since the numerator of a given fraction is 4 less than its denominator we have,

Numerator=Denominator-4

⇒ a=b-4

Since 3 is subtracted from the numerator and 5 is added to the denominator, the fraction becomes one by fourth we have

4(a-3)=1(b+5)

4a-12=b+5

4a-b=17

4(b-4)-b=17   ( ∵ a=b-4)

4b-16-b=17

3b=17+16

3b=33

⇒ b=11

Now put b=11 in a=b-4 we get

a=11-4

⇒  the fraction is a/b=7/11

3 0
3 years ago
Determine which of the following is a rectangle form of a complex number.
Varvara68 [4.7K]

Answer:

A) a+bi

Explanation:

Rectangular form of complex numbers is written as a+bi, where a and b are integers.

Rectangular form always has an integer piece, a, and a complex piece, bi.

4 0
3 years ago
The function f has first derivative given by f'(x)=(x)^1/2/1+x+x^3. What is the x-coordinate of the inflection point of the grap
Anestetic [448]
Inflection at f'(x) = 0 
<span>
x^1/2 / (1 + x + x^3) = 0 </span>

<span>The x coordinate is x = 0 </span>
<span>
or "C" from your choices there. </span>

<span>The simplest way is to notice that this happens when x = 0. The reason is you got: </span>
<span>
x^1/2 / (some expression) </span>
<span>
at x = 0 the numerator is 0 so unless the denominator is also 0 the result is 0. </span>
<span>
The denominator for x = 0 is 1 so you get </span>
<span>
0/1 = 0.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
4 0
3 years ago
An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

3d^2-18d+27 = 0

d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
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