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2 years ago

9

A TV production warehouse can assemble 120 TV’s in 4 hours. How long does it

1 answer:

nirvana33 [79]2 years ago

7 0

$\huge\boxed{2\ \text{minutes}}$

First, convert the number of hours to minutes.

$4*60=240$

Now, divide by the number of TVs assembled in that time.

$240\div 120=\boxed{2}$

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Wallace took out a $5,000 loan for six years. He is being charged 4 percent interest, compounded annually. Calculate the total a

statuscvo [17]

Wallace will pay $6,325 after 6 years.

Given:
Principal = 5,000
interest rate = 4%
Term = 6 years

Compound Interest means that the interest earned will also be earning its own interest.

Compound Interest = Principal x (1+r)^t
C.I. = 5,000 x 1.04⁶
C.I. = 5,000 x 1.265
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6,325 - 5,000 = 1,325 interest for 6 years.

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3 years ago

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Use triangles to find the sum of the interior angle measures of the polygon.

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Answer:

360 degrees

Step-by-step explanation:

2 90 degress triangles 180= 1 triangle 360=2 triangles since there is 2 we can conclude that it is 360 degrees

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2 years ago

___H2 + ___Br2 → ___HBr

Vaselesa [24]

Answer:H2+Br2-->2HBr

Step-by-step explanation:

The amount of atoms on the left side must be equal to the amount of atoms on the right side for each element.

On the left you got 2xH and 2xBr.

This means you must have the same amount on the right.

2HBr =2xH + 2xBr

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3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

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3 years ago

The sum of two numbers is 35. The greater number is 4 less than twice the lesser number. What is the greater number?

zubka84 [21]

Answer: x=13

Step-by-step explanation: ?+?=35

(2x-4)+x=35

3x-4=35

3x=35+4

3x=39

x=13

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3 years ago