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3 years ago

CAN SOMEONE PLEASE HELP ME WITH MY MATH !!!

Mathematics

2 answers:

AveGali [126]3 years ago

7 0

Answer:

Step-by-step explanation:

The similarity ratio is 22/ 10 and 33/y and 12/x

22/10 = 33/y cross multiply expressions 22y = 330 and y = 15

Sonja [21]3 years ago

5 0

Answer:

y = 15

Step-by-step explanation:

We can use ratios to solve

y 10

----- = ------------

33 22

Using cross products

22y = 10 *33

Divide each side by 22

22y/22 = 10 *33/22

y = 15

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Hi! How do you solve this? Step by step??

Mars2501 [29]

Answer:

Step-by-step explanation:

Substitue 3 for every x in the equation

10(3)-(3*3)(2*3)+(3)^2(2*3)

Multiply

30-(9)(6)+9(6)

30-54+54=30

7 0

3 years ago

Read 2 more answers

How much interest is earned on a principle of $864.27 invested at an interest rate of 8% for 3 years? Round to the nearest cent

amid [387]

Answer:

the interest =20.74

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<h2>HOPE IT HELPS YOU</h2>

7 0

3 years ago

60/30 in simplistic form Need answer quick!!!!!!!!!

makkiz [27]

Answer:

Step-by-step explanation:

60/30 is 2

HOpe this helps :D

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3 years ago

Verify that the dominant term in the operation count (number of multiplications or number of additions) for solving a lower tria

pantera1 [17]

Answer:

Attachment below

Step-by-step explanation:

5 0

3 years ago

Stephen uses \dfrac{2}{25}

zepelin [54]

Answer:

$13\dfrac{3}{4}$ servings$

Step-by-step explanation:

Stephen uses $\dfrac{2}{25}$ kilograms of tofu in each serving of his dish.

He has $1\dfrac{1}{10}$ kilograms of tofu.

We want to determine how many servings Stephen can make.

To do this, we divide the total weight of tofu by the weight per serving.

$\dfrac{\text{Total Weight(in kg)}}{\text{Weight(kg) per serving}} =\dfrac{1\dfrac{1}{10}}{ \dfrac{2}{25}}\\ = \dfrac{11}{10}\div \dfrac{2}{25}\\\\= \dfrac{11}{10}X \dfrac{25}{2}\\\\= \dfrac{11X25}{10X2}\\\\= \dfrac{275}{20}\\\\=13\dfrac{3}{4}$ servings$

Stephen can make $13\dfrac{3}{4}$ servings$ .

6 0

3 years ago

CAN SOMEONE PLEASE HELP ME WITH MY MATH !!!​

CAN SOMEONE PLEASE HELP ME WITH MY MATH !!!