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icang [17]
3 years ago
13

Easy question pls help​

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

They are congruent

Step-by-step explanation:

Vertical angels always congruent

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If f(x) = one-half left-bracket x right-bracket, what is f(7.6)? 3 3.5 3.8 4
Anton [14]

This is a method of substituting values into a given function. The value of the function f x is 7.6 is 3.8

<h3>Functions and values</h3>

Given the following function expressed as:

f(x) = 1/2(x)

We are to determine the value of f(7.6). Substitute x = 7.6 into the function as shown:

f(7.6) = 1/2(7.6)

f(7.6) = 7.6/2

f(7.6) = 3.8

Hence the value of the function f x is 7.6 is 3.8

Learn more on functions and values here:brainly.com/question/6561461

#SPJ4

5 0
2 years ago
​Select all of the following statements that are correct about the figures.
ArbitrLikvidat [17]

Answer:bbbvghj

Step-by-step explanation:lhgggffv

5 0
3 years ago
Read 2 more answers
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
3 years ago
What is the probability of selection for any man in a proportionate random sample, where a sample of 100 will be drawn from a po
kolbaska11 [484]
Working Principle: Stratified Random Sampling

nx = (Nx/N)*n

where:
    nx = sample size for stratum x
    Nx = population size for stratum x
    N = total population size 
    n = total sample size

Given:

  Nx = 100
  N = 1000
  n = 0.5*(1000) = 500

Required: Probability of Man to be selected

Solution:

nx = (Nx/N)*n
nx = (100/1000)*500 = 50 men

ny = (Nx/N)*n
ny = (100/1000)*500 = 50 women


Probability of Man to be selected = nx/(nx + ny)*100 = 50/(50+50)*100 = 50%

<em>ANSWER: 50%</em>
7 0
3 years ago
Someone please help. Will mark brainliest!
marusya05 [52]

Step 2, replace the perpendicular bisector with angle bisector.

Note that in Step 3, it says "bisectors" with an s. This means that there are more than one angle bisector. Step 1 only states 1 bisector, so above answer should be correct.

hope this helps

5 0
3 years ago
Read 2 more answers
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