Answer:
a) <em>C</em> Cu = 1588.6 mg/L
b) <em>C</em> Cu = 1588600 μg/L
c) this concentration exceeds the acute freshwater criteria:
<em>∴ C</em> Cu = 1588.6 mg/L >> 0.065 mg/L
Explanation:
<em>∴ C</em> Cu = 2.5 E-2 mol/L
∴Mw Cu = 63.546 g/mol
a) <em>C</em> Cu = 2.5 E-2 mol/L * 63.546 g/mol = 1.5886 g/L
⇒ <em>C</em> Cu = 1.5886 g/L * ( 1000 mg/g ) = 1588,6 mg/L
b) <em>C</em> Cu = 1588.6 mg/L * ( μg / 0.001 mg ) = 1588600 μg/L
c) <em>C</em> Cu = 65 ppb * ( ppm / 1000ppb ) = 0.065 ppm = 0.065 mg/L
∴ ppm ≡ mg/L
⇒ <em>C</em> Cu = 1588.6 mg/L >> 0.065 mg/L; this concentration exceeds the acute freshwater criteria