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ikadub [295]
2 years ago
9

What two aspects of a force do scientists measure?

Chemistry
2 answers:
Rashid [163]2 years ago
7 0

Answer: option c. magnitude and direction


Explanation:


1) Force is a vector: it has magnitude and direction.


2) Magnitude measures the "intensity" of the force. It is measured in newtons (N), in the SI (international system of units). One newton is the force exerted to confere an acceleration of 1 m/s² to a mass of 1 kg.


3) Telling the magnitude of the force is not enough information to understand what the force is and to predict its effect.


It is necessary to tell the direction in which the force is applied.


It is not the same a force of 10 N that pulls that the same magnitude pushing. And it is not the same a hhorizontal force of 100 N to move an object, than the same magnitude applied at an agle.


That is why the force must be measured and reported as a magnitude and a direction.


4) Examples of forces correctly reported are:


i) 100 N vertically upward


ii) 1000 N 20° to the east of the north.


iii) 0.2 N with an elevation angle of 50°.


Then, scientists must measure the magnitude and the direction of the force.

weeeeeb [17]2 years ago
7 0
<span>1.       </span><span>The answer is C.
It is the magnitude and the direction that the scientist considered to measure the aspect of force.
=> Magnitude can be describe in 3 terms.
In mathematics it is considered as the relative size of an object.
IN Astronomy, it is considered as the measure of brightness and differences of brightness in astronomy study
And in earthquake, it is a measure of the energy of earthquake.
=> Direction is a course or  an explicit instruction where a certain object move.</span>



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A balloon that can hold 85 L of air is inflated with 7.056 grams of H2 gas at a pressure of 101.3 kPa. What is the temperature,
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Temperature is 258.32°C

<h2>Explanation:</h2>

Using the ideal gas equation;

PV = nRT        --------------(i)

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V = Volume of the gas

n = number of moles of the gas

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T = Temperature

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Volume of the gas = 85L = 8.5 x 10⁻³m³

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<em><u>Steps:</u></em>

(i) Using the mass of the gas, calculate the number of moles using the relation:

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Where;

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M = Molar mass of H₂ = 1g/mol

<em>Substitute these values into equation (ii) as follows:</em>

n = 7.056g / (1g/mol)

n = 7.056mol

(ii) Now calculate the temperature of the balloon by substituting the necessary values into equation (i)

(1.013 x 10⁵Pa)(8.5 x 10⁻³m³) = (7.056mol) (8.31 J/mol · K)(T)

T = (1.013 x 10⁵Pa)(8.5 x 10⁻³m³) ÷ (7.056mol) (8.31 J/mol · K)

<em>Solving the above gives</em>

T = 14.68K

<em>Convert this to Celsius </em>

T = 273 - 14.68

T = 258.32°C

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