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2 years ago

What two aspects of a force do scientists measure?

Chemistry

2 answers:

Rashid [163]2 years ago

7 0

Answer: option c. magnitude and direction

Explanation:

1) Force is a vector: it has magnitude and direction.

2) Magnitude measures the "intensity" of the force. It is measured in newtons (N), in the SI (international system of units). One newton is the force exerted to confere an acceleration of 1 m/s² to a mass of 1 kg.

3) Telling the magnitude of the force is not enough information to understand what the force is and to predict its effect.

It is necessary to tell the direction in which the force is applied.

It is not the same a force of 10 N that pulls that the same magnitude pushing. And it is not the same a hhorizontal force of 100 N to move an object, than the same magnitude applied at an agle.

That is why the force must be measured and reported as a magnitude and a direction.

4) Examples of forces correctly reported are:

i) 100 N vertically upward

ii) 1000 N 20° to the east of the north.

iii) 0.2 N with an elevation angle of 50°.

Then, scientists must measure the magnitude and the direction of the force.

weeeeeb [17]2 years ago

7 0

1. The answer is C.
It is the magnitude and the direction that the scientist considered to measure the aspect of force.
=> Magnitude can be describe in 3 terms.
In mathematics it is considered as the relative size of an object.
IN Astronomy, it is considered as the measure of brightness and differences of brightness in astronomy study
And in earthquake, it is a measure of the energy of earthquake.
=> Direction is a course or an explicit instruction where a certain object move.

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1.062 mol/kg.

Step 1. Write the balanced equation for the neutralization.

MM = 204.22 40.00

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Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

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Step 3. Calculate the moles of NaOH

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Step 4. Calculate the mass of the NaOH

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Step 5. Calculate the mass of the water

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3 0

3 years ago

Twenty five grams of Iron 3 oxide react with an excess of carbon monoxide to form 15 g of Fe. Carbon dioxide is the other produc

densk [106]

<h3>Answer:</h3>

Theoretical mass = 17.42 g

Percent yield of Fe = 86.11%

<h3>Explanation:</h3>

The equation for the reaction between iron (iii) oxide and carbon monoxide is given by;

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

We are required to calculate the theoretical yield and the percentage yield of Iron.

Step 1: Moles of iron (iii) oxide

Moles are given by dividing the mass of the compound by the molar mass.

Molar mass of Iron(iii) oxide = 159.69 g/mol

Moles of Iron(III) oxide = 25 g ÷ 159.69 g/mol

= 0.156 moles

Step 2: Moles of Iron produced

From the equation 1 mole of Iron(iii) oxide reacts to produce 2 moles of Fe.

Therefore, the mole ratio of Fe₂O₃ to Fe is 1 : 2.

Thus, moles of Fe = Moles of Fe₂O₃ × 2

= 0.156 moles × 2

= 0.312 moles

Step 3: Theoretical mass of iron produced

To calculate the mass of iron we multiply the number of moles of iron with the relative atomic mass.

Relative atomic mass = 55.845

Mass of iron = 0.312 moles × 55.845

= 17.42 g

Step 4: Percent yield of iron

% yield = (Actual mass ÷ Theoretical mass)×100

= (15 g ÷ 17.42 g) × 100 %

= 86.11%

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3 years ago

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3 years ago

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

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Answer:

The mean free path = 2.16*10^-6 m

Explanation:

Given:

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

To determine:

The mean free path, λ

Calculation:

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

$\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m$

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3 years ago

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