Is sand biotic or abiotic

A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.

nata0808 [166]

The equilibrium constant for this reaction at 350°C is determined as 5.85.

<h3>Concentration of each component</h3>

concentration of bromine, C(Br) = 0.6 mol/1 = 0.6

concentration of iodine, C(I) = 1.6 mol/1 = 1.6

<h3>Create an ICE table</h3><h3>What is ICE table?</h3>

An ICE table is a tabular system of keeping track of changing concentrations in an equilibrium reaction.

ICE is an abbreviation that stands for initial, change, equilibrium.

Create ICE table for the reactants and products formed;

Br2(g) + I2(g) ↔ 2IBr(g)

I 0.6 1.6 0

C -1.19 -1.19 1.19

E 0.6 - 1.19 1.6 - 1.19 1.19

E = -0.59 0.41 1.19

<h3>Equilibrium constant </h3>

The equilibrium constant is calculated as follows;

KC = [IBr]²/[Br][I]

KC = (1.19²) / (0.59 x 0.41)

KC = 5.85

Thus, the equilibrium constant for this reaction at 350°C is determined as 5.85.

Learn more about equilibrium constant here: brainly.com/question/19340344

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4 0

2 years ago

In order to make 1 batch of cookies it requires 2 cups flour, 3 eggs, and 1 cup sugar. What would be the coefficients for the fl

DanielleElmas [232]

20 cups of flour, 30 eggs, and 10 cups of sugar

4 0

3 years ago

A sample of gas occupies 1.2 L at 12.0oC. Assuming pressure remains the same, what would be the volume (in L) of this gas at 67o

Levart [38]

Answer:

e.

6.7

hope it help

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4 0

3 years ago

Now if your lab partner determined that there were 1.552 x 1022 atoms of H in an unknown sample of C2H4Cl2, how many milligrams

STALIN [3.7K]

To determine the mass of the sample in milligrams in this problem, we use the avogadro's number to convert from atoms to moles, relate the moles of element in the sample to the mole present and the molar mass of the sample. We do as follows:

1.552 x 10^22 atoms H ( 1 mol H / 6.022x10^23 atoms H ) ( 1 mol C2H4Cl2 / 4 mol H ) ( 98.96 g C2H4Cl2 / 1 mol C2H4Cl2 ) = 0.625 g C2H4Cl2 = 625 mg <span>C2H4Cl2</span>

3 0

4 years ago

Charcoal from the dwelling level of the Lascaux Cave in France gives an average count of 0.97 disintegrations of ^14 C per minut

Verdich [7]

Answer:

Explanation:

count given by old sample = .97 disintegrations per minute per gram

count given by fresh sample = 6.68 disintegrations per minute per gram

Half life of radioactive carbon = 5568 years

rate of disintegration

dN / dt = λ N

In other words rate of disintegration is proportional to no of radioactive atoms present . As number reduces rate also reduces .