<u>The Ingredients required are...
</u>GBL (gamma-butyrolactone)
BD (butanediol)
GBL is an ingredient used when stripping paint
BD is an ingredient used in making plastics or adhesives
This drug is illegal because no one can detect it in a drink when dissolved in
<u>
</u><u>
</u>
Answer: Reaction A: pi + glucose ⇒ glucose-6-phosphate + H2O ΔG = 13.8 kJ/mol
Reaction B: pi + frutose-6-phosphate ⇒fructose-1,6-biphosphate + H2O ΔG = 16.3kJ/mol
Explanation: ΔG is the representation of the change in Gibbs Free Energy and relates enthalpy and entropy in a single value, which is:
ΔG = ΔH - TΔS
where:
ΔH is enthalpy
T is temperature
ΔS is entropy (measure of the )
It can also predict the direction of the reaction with the conditions of temperature and pressure being constant.
When the change is positive, the reaction is non-spontaneous, which means the reaction needs external energy to occur. If the change is negative, it is spontaneous, i.e., happens without external help.
Analyzing the reaction, we see that reaction A and B have a positive ΔG, while reaction C is negative, so the reaction that are unfavorable or nonspontaneous are <u>reactions A and B</u>.
2HF + Na2SiO3 ----> 2NaF + H2SiO3 is the balanced equation.
2 moles of HF form 2 moles of NaF
therefore 0.508 Mol HF forms 0.508 mol of NaF
In grams this is 0.508( rel atomic mass of Na + RAM of F)
= 0.508 (22.99+19)
= 21.33 grams
They both have the same atomic number
Answer:
the partial pressure of the O2 is 0.167 atm
Explanation:
The computation of the partial pressure of the O2 is shown below:
As we know that
P = P_N2 + P_O2 + P_CO2
P_O2 = P - P_N2 - P_CO2
= (1.007 - 0.79 - 0.05)
= 0.167 atm
Hence, the partial pressure of the O2 is 0.167 atm
we simply applied the above formula