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GenaCL600 [577]
3 years ago
8

Explain how the models you developed show that when methane combines with oxygen to form carbon dioxide and water, no atoms are

left over from the reaction.

Chemistry
1 answer:
Xelga [282]3 years ago
3 0

Answer: the bonds in the methane and oxygen come apart, the atoms rearrange and then re-bond to form water and carbon dioxide

Explanation:^

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Suppose that the gas-phase reactions A→B and B→A are both elementary processes with rate constants of 4.7×10−3s−1 and 5.8×10−1s−
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Answer:

K = 8.1 x 10⁻³

Explanation:

We are told here that these gas phase reactions are both elementary processes, thus the reactions forward and reverse are both first order:

A→B        Rate(forward) = k(forward) x [A]

and for

B→A       Rate(reverse) = k(reverse) x [B]

At equilibrium we know the rates of the forward and reverse reaction are equal, so

k(forward) x [A]  = k(reverse) x [B]    for A(g)⇌B(g)

⇒  k(forward) / k(reverse)  =  [B] / [A] =  K

4.7 x 10⁻³  s⁻1 / 5.8 x 10⁻¹ s⁻¹ = 8.1 x 10⁻³ = K

Notice how this answer is logical : the rate of the reverse reaction is greater than the forward reaction ( a factor of approximately 120 times) , and will be expecting a number for the equilibrium constant, K, smaller than one where the reactant concentration, [A], will prevail.

It is worth to mention that this is only valid for reactions which are single, elementary processes and not true for other equilibria.

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