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GenaCL600 [577]

3 years ago

8

Explain how the models you developed show that when methane combines with oxygen to form carbon dioxide and water, no atoms are

left over from the reaction.

1 answer:

Xelga [282]3 years ago

3 0

Answer: the bonds in the methane and oxygen come apart, the atoms rearrange and then re-bond to form water and carbon dioxide

Explanation:^

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SOMEONE PLS HELP ME ITS URGENT

Simora [160]

If copper is heated with iron oxide there is no obvious reaction because

copper is less reactive than iron.

On a reactivity chart, copper is far below iron. This makes it impossible for a replacement reaction to occur, so the equation doesn't change.

I hope I helped!

5 0

3 years ago

Read 2 more answers

const2013 [10]

Answer:

$\large \boxed{\text{-1276 kJ/mol}}$

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

CH₃CH₂OH + 3O₂ ⟶ 2CO₂ + 3H₂O

Bonds: 5C-H 1C-C 1C-O 1O-H 3O=O 4C=O 6O-H

D/kJ·mol⁻¹: 413 347 358 467 495 799 467

$\Delta H = \sum{D_{\text{reactants}}} - \sum{D_{\text{products}}}\\\sum{D_{\text{reactants}}} = 5 \times 413 + 1 \times 347 + 1 \times 358 + 1 \times 467 + 3 \times 495 = 3237 + 1485\\=\text{4722 kJ}\\\sum{D_{\text{products}}} = 4 \times 799 + 6 \times 467 =3196 + 2802 = \text{5998 kJ}\\\Delta H = 4722 - 5998= \textbf{-1276 kJ} \\ \text{The overall energy change is $\large \boxed{\textbf{-1276 kJ/mol}}$}.$

6 0

3 years ago

12. In a gas mixture consisting of carbon dioxide (CO2) and nitrogen (N2), the carbon dioxide molecules have a root-mean-square

zaharov [31]

Answer:

The correct answer is option e.

Explanation:

The formula used for root mean square speed is:

$\nu_{rms}=\sqrt{\frac{3kN_AT}{M}}$

where,

$\nu_{rms}$ = root mean square speed

k = Boltzmann’s constant = $1.38\times 10^{-23}J/K$

T = temperature

M = Molar mass

$N_A$ = Avogadro’s number = $6.02\times 10^{23}mol^{-1}$

Root mean square speed of carbon dioxide molecule:

$\nu_{rms}= 550 m/s$

Temperature of the mixture = T =?

Molar mass of carbon dioxide = 44 g/mol = 0.044 kg/mol

$\nu_{rms}=550 m/s=\sqrt{\frac{3\times 1.38\times 10^{-23}J/K\times 6.022\times 10^{23}mol^{-1}T}{0.044 kg/mol}}$

T = 533.87 K

Root mean square speed of nitrogen molecule:

$\nu'_{rms}= ?s$

Molar mass of nitrogen = 28 g/mol = 0.028 kg/mol

$\nu'_{rms}=\sqrt{\frac{3\times 1.38\times 10^{-23}J/K\times 6.022\times 10^{23}mol^{-1}\times 533.87 K}{0.028 kg/mol}}$

$\nu'_{rms}=689.46 m/s\approx 689 m/s$

689 m/s is the root-mean-square speed of the nitrogen molecules in the sample.

7 0

3 years ago

Erica is working in the lab. She wants to remove the fine dust particles suspended in a sample of oli. What method is she most l

patriot [66]

Erica is likely to use reverse osmosis process.it is the method used in the industry to treat water in oil and gas industry .or ultra filtration method is also employed

7 0

3 years ago

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What is the mass of 8.12×10 to the 23rd power molecules of CO2 gas

Maksim231197 [3]

Answer:

38.7 g is the answer to your question. Your welcome:)

4 0

3 years ago