CH4 + 2O2 --> CO2 + 2H2O
On the reactant side you start with 1 carbon, 4 hydrogen, and 2 oxygen. On the product side you start with 1 carbon, 2 hydrogen, and 3 oxygen. In order to get them equal, you need to put 2 in front of the H2O which equals out the number of Hydrogen on both sides. But Now we must balance the Oxygens. Because of the H2O we now have 4 Oxygens on the product side and only 2 on the reactant. In order to balance this, we put a 2 in front of the O2 giving us 4 hydrogen on both sides, Balancing the equation
I think this is what you're after:
Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1]
Convert to J and divide by the Avogadro Const to give E in J per photon
E = 375700/6.022×10^23 = 6.239×10^-19 J
Plank relationship E = h×ν E in J ν = frequency (Hz s-1)
Planck constant h = 6.626×10^-34 J s
6.239×10^-19 = (6.626×10^-34)ν
ν = 9.42×10^14 s^-1 (Hz)
IP are usually given in ev Cs 3.894 eV
<span>E = 3.894×1.60×10^-19 = 6.230×10^-19 J per photon </span>
It mean it consisted of 1 g of lead and 0.077 g of O2.
divide these numbers by molar mas.
1/82=0.012 Pb /0.004 = 3
0.077/16= 0.004 O /0.004 =1
Pb3O
